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2 years ago

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HELP 10pts!

1 answer:

masha68 [24]2 years ago

5 0

IM IN THAT CLASS TOO

Im abt to do it and ill send u all the answers when im

done, add me on sxxap or instaxxxgram so i can send it to u

my userneamen both: Bellaberrygood

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Would your results be he same if 1.5 g of barium chloride was used instead of 1.3 g? same with 0.7 g of barium chloride?

pickupchik [31]

For a chemical reaction, the results would be the same with different amounts of barium chloride present if barium chloride is not the limiting reactant of the reaction. The limiting reactant is the substance that is totally consumed when the reaction proceeds to completion. In other words, it dictates the amount of products that will be produced. Otherwise, if barium chloride is the limiting reactant, the amount of barium chloride present would definitely affect the results.

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3 years ago

What are the properties of water that make it unique

Vaselesa [24]

Answer:

Water is polar.

Water is an excellent solvent.

Water has a high heat capacity.

Water has a high heat of vaporization.

Water has cohesive and adhesive properties.

Water is less dense as a solid than as a liquid.

3 0

3 years ago

Calculate the number of moles of Cl2 produced at equilibrium when 3.98 mol of PCl5 is heated at 283.9 deg celsius in a vessel ha

ddd [48]

Answer:

1.274 moles

Explanation:

The equation for the reaction can be represented as follows:

$PCl_5(g)$ ⇄ $PCl_3(g)$ + $Cl_2(g)$

K = 0.060

K = $\frac{[PCl_3][Cl_2]}{[PCl_5]}$

Concentration of $PCl_5(g)$ = $\frac{numbers of moles}{volume}$

Concentration of $PCl_5(g)$ = $\frac{3.98}{10.0}$

Concentration of $PCl_5(g)$ = 0.398 moles

If we construct an ICE table for the above equation; we have:

$PCl_5(g)$ ⇄ $PCl_3(g)$ + $Cl_2(g)$

Initial 0.398 0 0

Change - x + x + x

Equilibrium (0.398 - x) x x

K = $\frac{[PCl_3][Cl_2]}{[PCl_5]}$

K = $\frac{[x][x]}{[0.398-x]}$

K = $\frac{x^2}{0.398-x}$

0.060 = $\frac{x^2}{0.398-x}$

0.06(0.398-x) = x²

0.02388 - 0.060x = x²

x² + 0.060x - 0.02388 = 0 (quadratic equation)

a = 1; b= 0.06; c= -0.02388

Using quadratic formula;

= $\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

= $\frac{-0.06+/-\sqrt{(0.06)^2-4(1)(-0.02388)} }{(2*1)}$

= $\frac{-0.060+/-\sqrt{0.0036+0.09552} }{2}$

= $\frac{-0.06+/-\sqrt{0.09912} }{2}$

= $\frac{-0.06+/-0.3148}{2}$

= $\frac{-0.060+0.3148}{2}$ or $\frac{-0.060-0.3148}{2}$

= $\frac{0.2548}{2}$ or $\frac{-0.3748}{2}$

= 0.1274 or -0.1874

We go by the positive value which says:

[x] = 0.1274 M

number of moles = 0.1274 × 10.0

= 1.274 moles

∴ the number of moles of Cl₂ produced at equilibrium = 1.274 moles

7 0

3 years ago

Select the reactants of photosynthesis

chubhunter [2.5K]

Answer:

glucose and oxygen are the reactants of photosynthesis

Explanation:

hope it helps you

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2 years ago

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Explanation:

I need a help of math.

please can someone help me ?

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2 years ago