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2 years ago

What kind of object are the light rays interacting with in the model below?

Physics

1 answer:

Ymorist [56]2 years ago

5 0

Answer:

Concave lens

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A powerful motorcycle can produce an acceleration of 3.00 m/s2 while traveling at 106.0 km/h. At that speed, the forces resistin

otez555 [7]

Answer:

"1155 N" is the appropriate solution.

Explanation:

Given:

Acceleration,

$a=3 \ m/s^2$

Forces resisting motion,

$F_f=432 \ N$

Mass,

$m = 241 \ kg$

By using Newton's second law, we get

⇒ $F-F_f=ma$

Or,

⇒ $F=ma+F_f$

By putting the values, we get

⇒ $=(3\times 241)+432$

⇒ $=723+432$

⇒ $=1155 \ N$

7 0

3 years ago

What type of change is wood to wood chip?

Vanyuwa [196]

Answer:

irriversible change.....

4 0

3 years ago

Read 2 more answers

Earth has a magnetic dipole moment of 8.0 × 1022 J/T. (a) What current would have to be produced in a single turn of wire extend

Lelechka [254]

Answer:

Answer is

A. I = 6.3×10^8 A

B. Yes

C. No

Refer below.

Explanation:

Refer to the picture for brief explanation.

7 0

3 years ago

Ryan is driving home from work and notices a deer leaping onto the road about 25 m in front of his car. He immediately applies t

Anvisha [2.4K]

Answer:

mu = 0.56

Explanation:

The friction force is calculated by taking into account the deceleration of the car in 25m. This can be calculated by using the following formula:

$v^2=v_0^2+2ax\\$

v: final speed = 0m/s (the car stops)

v_o: initial speed in the interval of interest = 60km/h

= 60(1000m)/(3600s) = 16.66m/s

x: distance = 25m

BY doing a the subject of the formula and replace the values of v, v_o and x you obtain:

$a=\frac{v^2-v_o^2}{2x}=\frac{0m^2/s^2-(16.66m/s)^2}{2(25m)}=-5.55\frac{m}{s^2}$

with this value of a you calculate the friction force that makes this deceleration over the car. By using the Newton second's Law you obtain:

$F_f=ma=(1490kg)(5.55m/s^2)=8271.15N$

Furthermore, you use the relation between the friction force and the friction coefficient:

$F_f= \mu N=\mu mg\\\\\mu=\frac{F_f}{mg}=\frac{8271.15N}{(1490kg)(9.8m/s^2)}=0.56$

hence, the friction coefficient is 0.56

6 0

3 years ago

What is the Unit used to measure voltage

muminat

The derived unit for voltage is named volt.

3 0

3 years ago