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fomenos
2 years ago
15

What kind of object are the light rays interacting with in the model below?

Physics
1 answer:
Ymorist [56]2 years ago
5 0

Answer:

Concave lens

.............

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Will give brainliest!!
givi [52]
A. Move the candle to the right, or the focal point to the left.

For a convex lens, the closer an object is to the focal point, the larger it’s image is (and therefore the greater the magnification is). The two ways you could make the candle be closer to the focal point are to move the candle to the right, or the focal point to the left.
4 0
3 years ago
At an instant when the displacement is equal to a/2, what fraction of the total energy of the system is potential?
madreJ [45]
<span>At an instant when the displacement is equal to a/2, Potential energy U = 1/2ka(square) where a is displacement. when a= a/2 U = 1/4ka(square) U = E/4 Potential Energy = 1/4 Total energy</span>
4 0
3 years ago
A group of students conduct an experiment with a block of wood sliding down an incline. They find that the final energy of the b
77julia77 [94]

Answer:

1) 51 m

2) Some energy was transformed to other forms. (This question)

3) 3.24 J

4) 45 J

5) 1020 J

Explanation:

100%

8 0
3 years ago
Two blocks of masses 3.0 kg and 5.0 kg are connected by a spring and rest on a frictionless surface. They are given velocities t
miskamm [114]

Answer:

-0.7 m/sec

Explanation:

Mass of first block = m1 =3.0 kg

Mass of second block = m2= 5.0 kg

Velocity of first block = V1= 1.2 m/s

Velocity of second block = V2 = ?

Momentum of Center of mass MVcom  is sum of both blocks momentum and is given by

MVcom= m1v1+m2v2

Where

M= mass of center of mass

Vcom= Velocity of center of mass=0 m/s (because center of mass is at rest , so Vcom = 0 m.sec)

Putting values, we get;

0= 3×1.2+5v2

==> v2=  3.6/5= - 0.7 m/s

-ve sign indicates that block 2 is moving in opposite direction of block 1

3 0
3 years ago
A red laser with a wavelength of 670 nm and a blue laser with a wavelength of 450 nm emit laser beams with the same light power.
tatyana61 [14]

E=hf C=wavelength*F

E=hC/wavelength

E=(6.626*10^-34)*(3.00*10^8)/670*10^-9

E=(6.626*10^-34)*(3.00*10^8)/450*10^-9

6 0
3 years ago
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