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Wittaler [7]
3 years ago
8

Which of these is an example of an abiotic factor?

Chemistry
1 answer:
dolphi86 [110]3 years ago
8 0

What are the choices? I'll answer once you tell me those

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which of the following pairs of elements could react to form an ionic compound? A. potassium and calcium B. sulfur and oxygen C.
Grace [21]
The correct option is FLUORINE AND COPPER.
An ionic compound is usually formed by the combination of a metal and a non metal, the metal usually act as an electron donor while the non metal act as an electron acceptor. Thus, in ionic compounds, there is total transfer of electrons from the metal to the non metal. In the question given here, copper is the metal while the fluorine is the non metal.<span />
4 0
3 years ago
2H2+ O2 —&gt; 2H2 O
lukranit [14]

Answer:bubuvuvuvftctcrchj

Explanation:

8 0
3 years ago
Calculate the freezing point of the solution containing 0.105 m k2s. calculate the boiling point of the solution above. -g
Licemer1 [7]
Quantity of K2S m = 0.105 m 
Number of ions i = 2(K) + 1(S) = 3
 Freezing point depression constant of water Kf = 1.86 
delta T = i x m x Kf = 3 x 0.105 x 1.86 = 0.586
 Freezing point = 0 - 0.586 = 0.586 C
 Boiling point constant of water Kb = 0.512
 delta T = i x m x Kb = 3 x 0.105 x 0.512 = 0.161
 Boiling point = 100 + 0.161 = 100.161 C
5 0
3 years ago
Read 2 more answers
A store employee first inflated a balloon with 1.53 moles of helium gas. When the customer said it needed to have a volume of 75
Leviafan [203]
The first volume milliliters are 328 mm
3 0
3 years ago
Cyclic compound A has molecular formula C5H10 and undergoes monochlorination to yield exactly three different constitutional iso
RideAnS [48]

Answer:

A: 1,2-dimethylcyclopropane

Explanation:

The possible cyclic structure with formula C₅H₁₀ are shown in the image.

A is a cyclic compound. On monochlorination, A yields 3 products.

To have 3 products on monochlorination, there should be three different carbon atoms.

Considering structure 1, all carbons have same nature, thus only one product will be formed and thus not a structure of A.

Considering structure 2, there are two different carbon atoms, thus two different structure are formed and thus not a structure of A.

Considering structures 3 and 4 , there are four different carbon atoms, thus four products will be formed and either of them are not a structure of A.

Considering structure 5, there are three different carbon atoms,  thus three different structure are formed and thus the A is structure 5.

4 0
3 years ago
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