Please help with the question attached I need it in an hour

How many moles of calcium chloride would react with 5. 99 moles of aluminum oxide?

slega [8]

There are 17.97 moles of calcium chloride would react with 5. 99 moles of aluminum oxide .

The balanced chemical equation between reaction between calcium chloride and aluminum oxide is given as,

$3CaCl_{2} (aq)+Al_{2} O_{3} (s)$ → $3CaO_{2} (s)+2Al Cl_{3} (aq)$

The molar ratio of above reaction is 3:1

It means 3 moles of calcium chloride is require to react one mole of aluminum oxide.

The number of moles of calcium chloride requires to react with 5. 99 moles of aluminum oxide = 3 × 5. 99 = 17.97 moles

The equation in which number of atoms of elements in reactant side is equal to the number of atoms of elements in product side is called balanced chemical equation .

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6 0

1 year ago

A teacher gives students four liquids commonly found in the kitchen - vinegar, apple juice, dish detergent, and milk - and pH in

VMariaS [17]

Answer:

1. Comparative

2. Independent variable

3. The pH is the Dependent variable

6 0

3 years ago

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Two substances with empirical formula HNO are hyponitrous acid (M = 62.04 g/mol) and nitroxyl (M = 31.02 g/mol).(b) For each spe

Natalija [7]

Below is an attachment of the Lewis structure with the lowest formal charges.

The formal charge is the fictitious charge that an atom in a molecule would have if the electrons in the bonds were evenly distributed among the atoms. The nonbonding electrons on a neutral atom are subtracted from its valence electron count, which is then followed by the number of bonds that bind it to other atoms in the Lewis structure, to get the formal charge. This is another way to put it. When hyponitrous acid is oxidized in the atmosphere, nitric and nitrous acids are produced. By reducing a nitrate or nitrite by sodium amalgam in the presence of water, hyponitrite salts have been created.

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6 0

2 years ago

For a particular reaction, Δ=−111.4 kJ and Δ=−25.0 J/K.

vichka [17]

Answer:

$\Delta G =-103.95kJ$

Explanation:

Hello there!

In this case, since the thermodynamic definition of the Gibbs free energy for a change process is:

$\Delta G =\Delta H-T\Delta S$

It is possible to plug in the given H, T and S with consistent units, to obtain the correct G as shown below:

$\Delta G =-111.4kJ-(298K)(-25.0\frac{J}{K}*\frac{1kJ}{1000J} )\\\\\Delta G =-103.95kJ$

Best regards!

6 0

3 years ago

PLEASE HELP ME, 20 POINTS

Marrrta [24]

Explanations:

Question 1: Lithium in 20.00+ g is C. or D., but 25.00+ g is D. which means this is the correct option.

I am unsure of Question 2. I don't think it is mole though.

Question 3: Boron in 25.00-30.00 g is B. or D., but 25.00 g would be C.

Question 4: 2.393 x 1024 atoms of Oxygen is 63.58 mole O. I don't know for sure, but I think this is correct.

I am NOT professional. There is a chance I am incorrect. Please reply to me if I've made a mistake.

4 0

2 years ago

Please help with the question attachedI need it in an hour​

Please help with the question attachedI need it in an hour