ILL GIVE BRAINLIST!!!!!!

Chemistry

2 answers:

attashe74 [19]4 years ago

7 0

Answer:

the investigation and results are more reliable if the results can be reproduced.

Explanation:

As you may already know, a scientific experiment is a set of procedures performed by a scientist who seeks to find answers to a particular phenomenon or situation. Every experiment, therefore, generates a result that seeks to explain a certain thing.

It is common and even recommended that scientists reproduce each other's experiments. This is because if, for example, an experiment done by me results in the same conclusions as an experiment done by you a few years ago, it means that the results of our experiments are credible and that they can be considered as correct and true.

fomenos4 years ago

3 0

hope this helpssss :)

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A possible mechanism for the overall reaction br2 (g) + 2no (g) → 2nobr (g) is no (g) + br2 (g) nobr2 (g) (fast) nobr2 (g) + no

givi [52]

The overall reaction is:
Br₂(g) + 2 NO(g) ↔ 2 NOBr(g)
rate law = k [Br₂][NO]²

The first step of the overall reaction is:
NO(g) + Br₂(g) K₁⇄⇄K-1 NOBr₂(g)
rate law 1 = k₁ [Br₂][NO] or
rate law 2 = k-1 [NOBr₂]

The second step of the overall reaction is:
NOBr₂(g) + NO(g) →K₂→ 2 NOBr
rate law 3 = k₂[NOBr₂][NO]

So, rate law of overall reaction can be obtained as follows:
(rate law 1)*(rate law 3) / (rate law 2)
= [(k₁[Br₂][NO])* (K₂[NOBr₂][NO])] / k₋₁[NOBr₂]
= [k₁k₂/k₋₁][NO]²[Br₂]
So the correct answer is:
[k₁k₂/k₋₁][NO]² [Br₂]

7 0

3 years ago

90 POINTSSSS!!!

Katarina [22]

Answer:

$\large \boxed{\text{-2043.96 kJ/mol}}$

Explanation:

Assume the reaction is the combustion of propane.

Word equation: propane plus oxygen produces carbon dioxide and water

Chemical eqn: C₃H₈(g) + O₂(g) ⟶ CO₂(g) + H₂O(g)

Balanced eqn: C₃H₈(g) + 5O₂(g) ⟶ 3CO₂(g) + 4H₂O(g)

(a) Table of enthalpies of formation of reactants and products

$\begin{array}{cc}\textbf{Substance} & \textbf{$\Delta_{\text{f}}$H/(kJ/mol}) \\\text{C$_{3}$H$_{8}$(g)} & -103.85 \\\text{O}_{2}\text{(g)} & 0 \\\text{CO}_{2}\text{(g)} & -393.51 \\\text{H$_{2}$O(g)} & -241.82\\\end{array}$

(b)Total enthalpies of reactants and products

$\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)\\= \text{-2147.81 kJ/mol - (-103.85 kJ/mol)}\\= \text{-2147.81 kJ/mol + 103.85 kJ/mol}\\= \textbf{-2043.96 kJ/mol}\\\text{The enthalpy change is $\large \boxed{\textbf{-2043.96 kJ/mol}}$}$

ΔᵣH° is negative, so the reaction is exothermic.

5 0

3 years ago

5. What is the molar mass of ethanol (C2H5OH)?

AVprozaik [17]

The molar mass is given by the sum of the atomic masses of the component elements of the substance.

In our case, the substance is ethanol or C₂H₅OH.

$A_C=12.011$

$A_H=1.0079$

$A_O=15.9994$

$\mathcal M_{C_2H_5OH} = 2 \times A_C + 6 \times A_H + A_O = 2 \times 12.011 + 6 \times 1.00079+ 15.999 4= 24.022 + 6.0474 + 15.9994= 46.069≈ \boxed{46.07 \dfrac{g}{mol}}$