Answer:
glucose
Explanation:
There are two types of respiration:
1. Aerobic respiration
2. Anaerobic respiration
Aerobic respiration:
It is the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.
Glucose + oxygen → carbon dioxide + water + 38ATP
Anaerobic Respiration:
It is the breakdown of glucose molecule in the absence of oxygen and produce small amount of energy. Alcohol or lactic acid and carbon dioxide are also produced as byproducts.
Glucose→ lactic acid/alcohol + 2ATP + carbon dioxide
This process use respiratory electron transport chain as electron acceptor instead of oxygen. It is mostly occur in prokaryotes. Its main advantage is that it produce energy (ATP) very quickly as compared to aerobic respiration.
Steps involve in anaerobic respiration are:
Glycolysis:
Glycolysis is the first step of both aerobic and anaerobic respiration. It involve the breakdown of one glucose molecule into pyruvate and 2ATP.
Fermentation:
The second step of anaerobic respiration is fermentation. It involve the fermentation of pyruvate into lactic acid or alcohol depending upon the organism in which it is taking place. There is no ATP produced in this step, however carbon dioxide is released.
Answer:
4–ethyl–2,3–dimethylheptane
Explanation:
To name the compound given above, do the following:
1. Locate the longest continuous carbon chain. This gives the parent name of the compound. In this case, the longest continuous carbon chain is 7. Thus the parent name is Heptane.
2. Identify the substituent group attached to the compound. In this case, the substituent group attached are:
a. Methyl (–CH₃). There are two methyl group attached.
b. Ethyl (–CH₂CH₃)
3. Locate the position of the substituent group attached to the compound by naming alphabetically.
a. The two Methyl (–CH₃) groups are located at carbon 2 and 3
b. The Ethyl (–CH₂CH₃) is located at carbon 4.
NOTE: The position of the Ethyl (–CH₂CH₃) group is the same from both side so we consider the lowest count for the methyl group.
4. Combine the above to obtain the name of the compound.
The name of the compound is:
4–ethyl–2,3–dimethylheptane
The answer is would be B! :)
