The statement is supported by the data, is that the youngest rocks on the seafloor were at the mid-ocean ridge.
<h3>
What is the evidence regarding the age of the rocks?</h3>
The data collected by scientists regarding rock ages along a mid-ocean ridge seafloor with mid-ocean ridge showing age of rock increasing the further from the ridge.
From the data, they found that the youngest rocks on the seafloor were at the mid-ocean ridge and the rocks get older with distance from the ridge crest.
Thus, the statement is supported by the data, is that the youngest rocks on the seafloor were at the mid-ocean ridge.
Learn more about age of rocks here: brainly.com/question/23546028
#SPJ1
Answer:
Proxima Centuri is 9 orders of magnitude further from New York compared to Perth
Explanation:
Distance of Proxima Centuri to New York = 4 × 10^16 meters
Distance of Proxima Centuri to Perth = 11000 miles
Since 1 mile = 1609 meters, distance to Perth in meters = 11000 × 1609
Distance to Perth = 17699000 = 1.7699 × 10^7 meters
Order of magnitude of the distances of Proxima Centuri to New York and Perth = 10^16/10^7
Order of magnitude = 10^9
Therefore, Proxima Centuri is 9 orders of magnitude further from New York compared to Perth.
Answer:
0.169
Explanation:
Let's consider the following reaction.
A(g) + 2B(g) ⇄ C(g) + D(g)
We can find the pressures at equilibrium using an ICE chart.
A(g) + 2 B(g) ⇄ C(g) + D(g)
I 1.00 1.00 0 0
C -x -2x +x +x
E 1.00-x 1.00-2x x x
The pressure at equilibrium of C is 0.211 atm, so x = 0.211.
The pressures at equilibrium are:
pA = 1.00-x = 1.00-0.211 = 0.789 atm
pB = 1.00-2x = 1.00-2(0.211) = 0.578 atm
pC = x = 0.211 atm
pD = x = 0.211 atm
The pressure equilibrium constant (Kp) is:
Kp = pC × pD / pA × pB²
Kp = 0.211 × 0.211 / 0.789 × 0.578²
Kp = 0.169
The volume could be calculated by using <span>V = n RT / P </span>
In which V = Volume
n = number of Moles
R= The Gas constant
T = Temperature (ideally this would be in Kelvin, but i don't see it in the option)
P = Pressure
I believe the answer is
<span>V = (1.5mol) (0.08205 L*kPa/K*mol) (22Celsius)/100 kPa
</span>
By the object's composition and the acting agent to which factors the change of the substance or entity.
<span>The effect of physical property of matter on the object or substance can be better identified when the object doesn't change in composition or in nature. Unlike chemical property which has changed in its composition and atomic structure that was caused by chemical change or reaction due to an agent. Physical property is identified thru physical reactions or changes that has never changed the object in an atomic level, like cutting paper into smaller sizes. The aforementioned example illustrates physical proerty but being cut into smaller buts without changing the object from paper to any other substance, thus, its structure remain and its still called paper regardless of size, mass and texture. <span>
</span></span>