How many orbitals are in a d sublevel?

A uniform cylinder of mass 4.3 kg and radius 0.4 m rolls down a ramp inclined at an angle 0.15 radians to the horizontal. what i

tester [92]

The cylinder's acceleration is

$a=\frac{gsin}{1+\frac{I}{mrL} }$

$= 2g\frac{sin}{3}$ θ

$= \frac{2(9.8) sin (0.15 rad)}{3} \\=0.9763 \frac{m}{sec r}$

<h3>How do you determine a cylinder's acceleration?</h3>

The cylinder's complete radius, $R$ , from the center marks the contact point, therefore the torque created by friction is given by $fR = I\alpha$ , where is the rotating acceleration. This rotational acceleration's corresponding linear acceleration, $\alpha$ , is equal to $R$ . The cylinder, which has its mass concentrated in its center, triumphs in the competition, followed by the disc and the hoop, with their respective final velocities being roughly $1.4:1.2:1$ . We can also see that our findings are unaffected by the cylinders' masses.

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5 0

2 years ago

If you were to measure the mass of magnesium and hydrochloric acid before combining them in the test tube, how would that mass c

SIZIF [17.4K]

The balanced chemical reaction for the system given is as follows:

2Mg + 2HCl = 2MgCl + H2

The mole ratio of the reactants is one is to one which means with a given amount of magnesium requires the same amount of hydrochloric acid to have a complete reaction. If supplied exactly, then after the reaction, all of the reactants are consumed and formed into the products.

5 0

3 years ago

Read 2 more answers

In a solution of pure water, the dissociation of water can be expressed by the following: H2O(l) + H2O(l) ⇌ H3O+(aq) + OH−(aq) T

kakasveta [241]

Answer:

[H₃O⁺] = 2.90 × 10⁻¹⁰ M

Explanation:

1) Ionization equilibrium equation: given

H₂O(l) + H₂O(l) ⇌ H₃O⁺(aq) + OH⁻(aq)

2) Ionization equilibrium constant, at 25°C, Kw: given

Kw = 1.0 × 10⁻¹⁴

3) Stoichiometric mole ratio:

As from the ionization equilibrium equation, as from the fact it is stated, the concentration of both ions, at 25°C, are equal:

[H₃O⁺(aq)] = [OH⁻(aq)] = 1.0 × 10⁻⁷ M

⇒ Kw = [H3O⁺] [OH⁻] = 1.0 × 10⁻⁷ × 1.0 × 10⁻⁷ = 1.0 × 10⁻¹⁴ M

4) A solution has a [OH⁻] = 3.4 × 10⁻⁵ M at 25 °C and you need to calculate what the [H₃O⁺(aq)] is.

Since the temperature is 25°, yet the value of Kw is the same, andy you can use these conditions:

Kw = 1.0 × 10⁻¹⁴ M², and

Kw = [H3O⁺] [OH⁻]

Then you can substitute the known values and solve for the unknown:

1.0 × 10⁻¹⁴ M² = [H₃O⁺] × 3.4 × 10⁻⁵ M

⇒ [H₃O⁺] = 1.0 × 10⁻¹⁴ M² / ( 3.4 × 10⁻⁵ M ) = 2.9⁻¹⁰ M

As you see, the increase in the molar concentration of the ion [OH⁻] has caused the decrease in the molar concentration of the ion [H₃O⁺], to keep the equilibrium law valid.

6 0

3 years ago

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Which item does not depend on rare earth elements?

Alisiya [41]

Answer:

Perrous magnets

Explanation:

6 0

2 years ago

Is malachite A mineral, a rock or neuter

dybincka [34]