You<span> should </span>test<span> FC and PH as soon as </span>you<span> take the sample</span>
Answer:
205N
Explanation:
The net force (F) is the difference between the applied force(
) and the kinetic frictional force(
). i.e
F =
-
-----------------(i)
Note that;
= μmg
Where;
μ = coefficient of kinetic friction
m = mass of the body
g = acceleration due to gravity = 10m/s²
Equation (i) then becomes;
F =
- μmg -------------------(ii)
<em>Given from question;</em>
m = mass of motorcycle = 150kg
μ = 0.03
= 250N
Substitute these values into equation (ii) as follows;
F = 250 - (0.03 x 150 x 10)
F = 250 - (45)
F = 205N
Therefore, the net force applied to the motorcycle is 205N
Answer:
a) 17.8 m/s
b) 28.3 m
Explanation:
Given:
angle A = 53.0°
sinA = 0.8
cosA = 0.6
width of the river,d = 40.0 m,
the far bank was 15.0 m lower than the top of the ramp h = 15.0 m,
The river itself was 100 m below the ramp H = 100 m,
(a) find speed v
vertical displacement

putting values h=15 m, v=0.8
............. (1)
horizontal displacement d = vcosA×t = 0.6×v ×t
so v×t = d/0.6 = 40/0.6
plug it into (1) and get

solving for t we get
t = 3.734 s
also, v = (40/0.6)/t = 40/(0.6×3.734) = 17.8 m/s
(b) If his speed was only half the value found in (a), where did he land?
v = 17.8/2 = 8.9 m/s
vertical displacement = 
⇒ 
t = 5.30 s
then
d =v×cosA×t = 8.9×0.6×5.30= 28.3 m
Answer:
12.5 m/s
Explanation:
In a acceleration time graph the area under the curve gives the change in velocity of the object. Here object starts at rest and therefore initial velocity is 0. After 5 seconds acceleration is 5m/s2.
change in velocity=area under the curve
change in velocity= 0.5*acceleration* change in time
v-0=0.5*5*5
v=12.5 m/s
Answer:
the final velocity of the object is 53.04 m/s.
Explanation:
Given;
initial velocity of the projectile, u = 50 m/s
displacement of the object, d = 16 m
let the final velocity of the object = v
Apply the following kinematic equation to determine the final velocity of the projectile.
v² = u² + 2gd
v² = 50² + (2 x 9.8 x 16)
v² = 2813.6
v = √2813.6
v = 53.04 m/s
Therefore, the final velocity of the object is 53.04 m/s.