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The answer you are looking for.....
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5.3025kg!</span>
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Answer:
Explanation:
Mass of first cart M1=2.4kg
Velocity of first cart U1=4.1m/s
Mass of second cart M2=1.7kg
Second cart is initially at rest U2=0
After an instant, the velocity of the second cart is U2=-2.8m/s
Now after collision the two cart move together with the same velocity I.e inelastic collision
Using conservation of momentum
Momentum before collision, = momentum after collision
M1U1 + M2U2 = (M1+M2)V
2.4×4.1 + 1.7× -2.8 =(2.4+1.7)V
9.84 - 4.76 = 4.1V
5.08=4.1V
V=5.08/4.1
V=1.24m/s
The momentum of the two cart at that instant is
M1U1+M2U2
2.4×4.1 + 1.7× -2.8
9.84 - 4.76
5.08kgm/s
So the momentum at the instant the velocity is 4.1m/s for cart 1 and -2.8m/s for cart 2 is 5.08kgm/s
Answer:
d = 10.076 m
Explanation:
We need to obtain the velocity of the ball in the y direction
Vy = 24.5m/s * sin(35) = 14.053 m/s
To obtain the distance, we use the formula
vf^2 = v0^2 -2*g*d
but vf = 0
d = -vo^2/2g
d = (14.053)^2/2*(9.8) = 10.076 m
Answer:
First and last one,
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