Note: I'm not going to type in case sensitive or correct grammer so it's not my fault if you paste my answer and the program says it's wrong
y=mx+b
m=slope
b=y intercept
the x intercept is where the line crosses the x axis or where y=0
the y intercept is where the line crosses the y axis or where x=0
so
for the slope, solve for y
Ax+By=C
minus Ax both sides
By=-Ax+c
divide both sides by B
the slope is
and the y intercept is at
find x intercept
set y=0
Ax+By=C
Ax+B(0)=C
Ax=C
divide both sides by A
the x intercept is at
or the point
slope is
the x intercept is at
or the point
the y intercept is at
or the point
The mean and range for class A are 84.4 and 20 while the mean and range for class B are 83.6 and 8. Class B is more consistant then class A.
<h3>How to calculate the mean?</h3>
We can see from the data that the consistency of class B is more becuase the repeatation of the same score is more in class B then class A and the range of class B is also less then the class A.
It should be noted that mean simply means average. It's the addition of the numbers divided by the total numbers.
In this case, the computation will be:
Class A: Mean = 422/5= 84.4.
Range: 94-74 = 20
Class B: Mean = 418/5 = 83.6.
Range= 88-80 = 8
Learn more about mean on:
brainly.com/question/1136789
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A. For the first two questions, there are 2 choices, true and false. The three questions will have 3 choices. The number of ways that student can complete the test is,
n = 2 x 2 x 3 x 3 x 3
n = 108
Answer: C. 108
B. From 0 to 9, there are 10 digits. There are also 26 and as per given, there are 4 symbols. The number of ways that the code can be made is,
n = 10 x 9 x 26 x 25 x 4
n = 234,000
Answer: C. 234,000
C. In the word, EXPERIMENT, there are 10 letters. Three of which are letter Es. The number of ways that the letters can be arranged is,
n = 10!/3!
n = 604,800
Answer: D. 604,800
D. If the arrangement is not important and that only the combination is important, the number of ways that the instructor can send 4 out of the 11 is,
n = 11C4 = 330
Answer: A. 330
E. If only one of the five keys can start the car then, the probability that the chosen key can start the car is equal to the ratio of the number of key to the total number of keys.
n = (1/5)(100%) = 20%
Answer: C. 20%
F. The events of picking the winning card and picking or choosing the losing card are complementary events such that the sum of their probabilities should be equal to 1 or 100%.
P = 100 - (2.9%)
P = 97.1%
Answer: D. 97.1%
Answer:
a = 12.594678463488691
c = 17.058934471398032
Step-by-step explanation:
A = 42
B = 73
C = 65
which is a total of 180
a = 12.594678463488691
b = 18
c = 17.058934471398032