It's "C" a sample of dust particles at 0 Pascals
<h2>
Hello!</h2>
The answer is:
The empirical formula is the option B. 
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Why?</h2>
The empirical formula of a compound is the simplest formula that can be written. On the opposite, the molecular formula involves a variant of the same compound, but it can be also simplified to an empirical formula.

We are looking for a formula that cannot be simplified by dividing the number of molecules/atoms that conforms the compound.
Let's discard option by option in order to find which formula is an empirical formula (cannot be simplified)
A. 
It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

B. 
It's an empirical formula since it cannot be obtained by the multiplication of a whole number and the simplest formula. It's the simplest formula that we can find of the compound.
C. 
It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

D. 
It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

Hence, the empirical formula is the option B. 
Have a nice day!
Matter is a slightly archaic word for something with mass, as in the conservation of matter (which must be paired with the conservation of energy to still hold true. Mass can be converted back and forth between energy, so therefore so can matter. Of course relativistic mass is conserved as it's a function of the energy of an object in that reference frame.
Zn(s) + 2HCl(aq) = ZnCl₂(aq) + H₂(g)
zinc + hydrochloric acid = zinc chloride + hydrogen
Answer:
(a) ml = 0, ±1, ±2
(b) ml = 0
(c) ml = 0, ±1, ±2, ±3, ±4
Explanation:
The rules for electron quantum numbers are:
1. Shell number, 1 ≤ n
2. Subshell number, 0 ≤ l ≤ n − 1
3. Orbital energy shift, -l ≤ ml ≤ l
4. Spin, either -1/2 or +1/2
So in our exercise,
(a) l = 2; equivalent with with sublevel <em>d</em>
-l ≤ ml ≤ l, ml = 0, ±1, ±2, equivalent with dxy, dxz, dyz, dx2-y2, dz2
(b) n = 1;
n = 1, only 01 level
l = 0, equivalent with sublevel <em>s</em>
ml = 0
(c) n = 4, l = 3.
l = 3, equivalent with sublevel <em>f</em>
ml = 0, ±1, ±2, ±3, ±4