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3 years ago

The major role meiosis plays in chromosomal inheritance is to

Biology

1 answer:

andrezito [222]3 years ago

5 0

Answer:

Doubles the amount of DNA and reduces the chromosome number from 2N to N.

Explanation:

Meiosis is a cell division in which one cell divides into 2 cells in the first meiotic division and then these two cells divide into two more cells so overall 4 cells are produced from one cell. This division occurs in gamete cells.

First, the amount of DNA gets double by converting the single-stranded DNA into double-stranded DNA. Then the homologous chromosomes get separated into two different cells in the first meiotic division and till now the chromosome number is 2N.

After the second meiotic division, each sister chromatids of a chromosome gets separated into separate cells and the chromosome number in daughter cells becomes 1 N. So the major role of meiosis is to double the DNA mount and reduce the chromosome number by half in all daughter cells.

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A wind instrument is a musical instrument that contains some type of resonator (usually a tube), in which a column of air is set into vibration by the player blowing into (or over) a mouthpiece set at or near the end of the resonator. The pitch of the vibration is determined by the length of the tube and by manual modifications of the effective length of the vibrating column of air. In the case of some wind instruments, sound is produced by blowing through a reed; others require buzzing into a metal mouthpiece.

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3 years ago

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3 years ago

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Anni [7]

Answer:

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1 year ago

How many possible open reading frames (frames without stop codons) are there that extend through the following sequence? 5'... C

fenix001 [56]

Answer:

There are 4 reading frames without stop codons.

Explanation:

1) To find the possible reading frames you need to separate your sequence in codons (trios) for the 5'-> 3' sense, first, excluding the first nucleotide, then excluding 2 nucleotides and then not excluding nucleotides.

5'... C TTA CAG TTT ATT GAT ACG GAG AAG G... 3' NO STOP CODON

5'... CT TAC AGT TTA TTG ATA CGG AGA AGG... 3' NO STOP CODON

5'... CTT ACA GTT TAT TGA TAC GGA GAA GG... 3'

2)Then you find the complementary sequence (which you already have)

3'... GAA TGT CAA ATA ACT ATG CCT CTT CC... 5'

3'... GA ATG TCA AAT AAC TAT GCC TCT TCC... 5'

3'... G AAT GTC AAA TAA CTA TGC CTC TTC C... 5'

3) Next, you have to obtain the reverse complementary

CCT TCT CCG TAT CAA TAA ACT GTA AG NO STOP CODON

CC TTC TCC GTA TCA ATA AAC TGT AAG NO STOP CODON

C CTT CTC CGT ATC AAT AAA CTG TAA G

4)Now you need to find start (AGT in terms of DNA) and stop codons(TAA, TAG, TGA, also in terms of DNA), in 5->3 and de reverse complementary.

As you can see, you have for open reading frames that lack of stop codon, unfortunately, they also lack of AGT, the start codon.

I added a table where you can find thestart and stop codons as well as the proteins that they translate to in terms of RNA.

I hope you find this information interesting and useful, good luck!

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3 years ago