the area and volume of the Pyramid of Gaza are 139, 840 m²
and 52950 m³ respectively.
<h3>How to determine the parameters</h3>
The formula for volume and area of a square pyramid are given thus;
Volume, V=
Area ,
Where
- a is the base length
- h is the height
Substitute the values;
Area =
Area =
Area =
Area = 52900 + 86, 940
Area = 139, 840 m²
Volume , v =
Volume = 52900 + 50
Volume = 52950 m³
Thus, the area and volume of the Pyramid of Gaza are 139, 840 m²
and 52950 m³ respectively.
Learn more about a square pyramid here:
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There are two different ways we can read your question.
Each way has a different answer.
Here it is both ways:
Way #1: (12 + 4n) / 3 = 8
Multiply each side by 3 : 12 + 4n = 24
Subtract 12 from each side: 4n = 12
Divide each side by 4: n = 3 .
====================================
Way #2: 12 + 4n/3 = 8
Subtract 12 from each side: 4n/3 = -4
Multiply each side by 3: 4n = -12
Divide each side by 4: n = - 3
First find the volume of the cylinder, then the volume of the cone, and after you can add the two volumes.
Cylinder:
V = π r^2 h
h = 12 inches
r = 4 inches
V = π(4^2)(12)
V = 192π
Cone:
V = 1/3 π r^2 h
h = 6 inches
r = 4 inches
V = 1/3 π (4^2)(6)
V = 32π
Now adding the two volumes, 192π + 32π = 224π cubic inches
3.97 rounded to the nearest hundreth so first you find the hundreth place then you look to the right so the number in the hundreth place is the 7 so when we look to the right we see nothing so we say theres a zero. So the seven would stay the same the answer is 3.97
Answer:
25/2985984
Step-by-step explanation:
12^4*30^8*125^2/(128^4*625^3*27^6)
(2^2*3)^4*(2*3*5)^8*(5^3)^2/(2^7)^4*(5^4)^3*(3^3)^6)
(2^8*3^4*2^8*3^8*5^8*5^6)/(2^28*5^12*3^18)
2^(8+8-28)*3^(4+8-18)*5^(8+6-12)
2^-12*3^-6*5^2
25/(2^12*3^6)
25/2985984