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olga55 [171]
4 years ago
13

As an object in motion becomes heavier, its kinetic energy _____. A. increases exponentially B. decreases exponentially C. incre

ases proportionally D. decreases proportionally
Physics
2 answers:
diamong [38]4 years ago
4 0

Answer:

USE SOCRACTIC IT WOULD REALLY HELP

Aleksandr-060686 [28]4 years ago
3 0
The answer is c. as an object is in motion speeds up or “becomes heavier”, it’s kinetic energy increases proportionally: double the velocity and you quadruple the kinetic energy. this is why a tiny bullet traveling at high speed does so much more damage than a huge truck bumping into something at 1 mph. so the answer is c
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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Solnce55 [7]

I think the correct answer is D: Potential Energy.

3 0
3 years ago
Read 2 more answers
a 700k/g race car slowed down from 30m/s to 15m/s what is the impulse and what was the average force applied by the brakes
posledela
So impulse is a change in momentum.

Mass*(final velocity - initial velocity)

I dont think you will be able to find the average force with the given info because you need to know the time it takes for the car to slow down.
5 0
4 years ago
A 4kg rock isn’t rolling 10m/s. Find it’s kinetic energy.
scoundrel [369]

Kinetic energy = (1/2) (mass) (speed)²

The rock's kinetic energy is not 

                           (1/2) (4 kg) (10 m/s)²

                      =   (1/2) (4 kg) (100 m²/s²)

                      =         200 Joules .

It may be more, or it may be less.  The only thing
we can be sure of is that it is not 200 Joules.
3 0
3 years ago
What is the concentration of the 100 g of solution having 25 g of solute?
Alexus [3.1K]

Answer:

70%

Explanation:

it's 70% hope it helps

8 0
2 years ago
the time required for one cycle, a complete motion that returns to its starting point, it called the_____. period medium frequen
Salsk061 [2.6K]

Answer:

The time required for one cycle, a complete motion that returns to its starting point,it is called periodic motion

Explanation:

I hope this will help you:)

3 0
4 years ago
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