Answer: balanced reaction equation
C8H18(g) + 25/2 O2(g) ---------> 8CO2(g) + 9H2O(l)
Explanation:
Part A- coefficients
1, 25/2,8,9
Part B
Oxygen is the limiting reactant
Part C
If 1 mole of octane produced 9 moles of water from the balanced reaction equation
0.28 moles of octane will produce 0.28×9= 2.52 moles of water
Part D
If 12.5 moles of oxygen reacts with 1 mole of octane
0.63 moles of oxygen will react with 0.63/12.5=0.0504moles of octane
Amount of octane left= 0.280-0.0504=0.2296 moles
There are 0.55 moles in glucose
Answer:
Yes, it is possible. Let us consider an example of two solutions, that is, solution A having 20 percent mass RbCl (rubidium chloride) and solution B is having 15 percent by mass NaCl or sodium chloride.
It is found that solution A is having more concentration in comparison to solution B in terms of mass percent. The formula for mass percent is,
% by mass = mass of solute/mass of solution * 100
Now the formula for molality is,
Molality = weight of solute/molecular weight of solute * 1000/ weight of solvent in grams
Now molality of solution A is,
m = 20/121 * 1000/80 (molecular weight of RbCl is 121 grams per mole)
m = 2.07
Now the molality of solution B is,
m = 15/58.5 * 1000/85
m = 3.02
Therefore, in terms of molality, the solution B is having greater concentration (3.02) in comparison to solution A (2.07).
