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kykrilka [37]
3 years ago
6

Consider the structure of the amino acid alanine. indicate the hybridization about each interior atom.

Chemistry
2 answers:
OLEGan [10]3 years ago
5 0
The structure of Alanine is shown below,
Except the carbon atom of carbonyl group which is Sp² Hybridized, all remaining atoms are Sp³ Hybridized. The hybridization of each element is depicted in a box below,

Brilliant_brown [7]3 years ago
5 0

Answer:

Alanine is composed of three carbon atoms , two oxygen atoms ,one nitrogen atom and seven hydrogen atoms with chemical formula of   C_3H_7NO_2 , with structure shown in image attached.

C-1 atom is sp^3 hybridized as it can form  four single bonds to give four hybridized orbitals.

C-2 atom is sp^3 hybridized as it can form  four single bonds to give four hybridized orbitals.

C-3 atom is sp^2 hybridized as it can form two single bonds to give three hybridized orbitals .

N atom is sp^3 hybridized as it can form three single bonds to give four hybridized orbitals out of which one hybridized orbitals is occupied by the lone pair of the nitrogen atom.

O-1 atom is sp^2 hybridized which means there are three hybridized orbitals out of which two of the hybridized orbitals are occupied by the two lone pairs of the oxygen atom.

O-2 atom is sp^3 hybridized as it form two single bonds to give four hybridized orbitals out of which two of the hybridized orbitals are occupied by the two lone pairs of the oxygen atom .

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If the change in entropy of the surroundings for a process at 451 k and constant pressure is -326 j/k, what is the heat flow abs
Arisa [49]

If the change in entropy of the surroundings for a process at 451 k and constant pressure is -326 j/k, then heat flow absorbed (in kj) by the system is -147.026kJ.

<h3>What is entropy? </h3>

The entropy of particle is defined as how random it move. It shows the randomness of the system or may be disorders of the system. It is used to measure the unavailable energy for performing useful work.

Unit of entropy = J/K

<h3>Formula:</h3>

∆s = ∆Q/T

where,

∆s = change in entropy of the surrounding = -326J/K

∆Q = heat absorbed from surrounding

T = Temperature = 451K

∆Q = ∆s × T

∆Q = -326 × 451

∆Q = 147,026 J

∆Q = 147.026 kJ

Thus we find that the heat absorbed by the system is 147.026 kJ.

learn more about entropy:

brainly.com/question/14131507

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8 0
2 years ago
The amount of radioactive carbon-14 in a sample is measured using a Geiger counter, which records each disintegration of an atom
sergij07 [2.7K]

Answer:

4121 years

Explanation:

From;

0.693/t1/2 = 2.303/t log No/N

t1/2= half life of the carbon-14

No= count rate of the living tissue

N= count rate of the sample

t = age of the sample

0.693/5730 =2.303/t log (13.5/8.2)

1.21 * 10^-4 = 2.303/t * 0.2165

1.21 * 10^-4 = 0.4986/t

t = 0.4986/1.21 * 10^-4

t = 4121 years

7 0
3 years ago
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Taya2010 [7]
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a_sh-v [17]

Answer: 65.23

Explanation:

3 0
3 years ago
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Slav-nsk [51]

Balanced equation for the reaction between ammonia and sulphuric acid is:

Explanation:

2NH3+H2SO4→(NH4)2SO4

I hope it'll help you...

8 0
2 years ago
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