The structure of Alanine is shown below, Except the carbon atom of carbonyl group which is Sp² Hybridized, all remaining atoms are Sp³ Hybridized. The hybridization of each element is depicted in a box below,
Alanine is composed of three carbon atoms , two oxygen atoms ,one nitrogen atom and seven hydrogen atoms with chemical formula of , with structure shown in image attached.
atom is hybridized as it can form four single bonds to give four hybridized orbitals.
atom is hybridized as it can form four single bonds to give four hybridized orbitals.
atom is hybridized as it can form two single bonds to give three hybridized orbitals .
atom is hybridized as it can form three single bonds to give four hybridized orbitals out of which one hybridized orbitals is occupied by the lone pair of the nitrogen atom.
atom is hybridized which means there are three hybridized orbitals out of which two of the hybridized orbitals are occupied by the two lone pairs of the oxygen atom.
atom is hybridized as it form two single bonds to give four hybridized orbitals out of which two of the hybridized orbitals are occupied by the two lone pairs of the oxygen atom .
2Ca + O2 = 2CaO First, determine which is the excess reactant 72.5 g Ca (1 mol) =1.8089725036 (40.078 g)
65 g O2 (1 mol) =2.0313769611 (15.999g × 2) Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.
Now do the stoichiometry 72.5 g Ca (1 mol Ca) (1 mol O2) (40.078 g Ca)(2 mol Ca)(31.998g O2)