Answer:
Vagus nerves
Explanation:
The vagus nerves are the tenth pair of cranial nerves
Scientists assume the gravitational force as negligible as compared to other forces present in the an atom because its value would be very small. Gravitational force is directly proportional to the mass of an object so small mass would lead to small force as well which is true for an atom. As compared to the nuclear forces, it would have a very small value.
Answer:
C. The motor tasks performed in the experiment were too simple.
On this case is the best option since the student wants to explain the effect of motor imagery and action observation together into the excitability. And maybe is too simple, since we need to cover other possibilities in order to analyze the excitability.
Explanation:
A. The procedure used did not include MEP recordings prior to each task.
Not true, is not a requisite record MEP prior to the task to evaluate the variable of interest on this case.
B. MEP amplitudes in an individual are typically highly consistent.
The Motor evoked potentials (MEP) "are electrical signals recorded from neural tissue or muscle after activation of central motor pathways". But on this case that's a technical aspect related to the topic and this not would be the reason why we need to withhold the presentation
C. The motor tasks performed in the experiment were too simple.
On this case is the best option since the student wants to explain the effect of motor imagery and action observation together into the excitability. And maybe is too simple, since we need to cover other possibilities in order to analyze the excitability.
D. The six different conditions were run in random order.
That's not true the student are not analyzing 6 different conditions, just 2.
Answer:
The correct answer is d
Explanation:
In this exercise they ask us which statement is correct, for this we plan the solution of the problem, this is a Doppler effect problem, it is the frequency change due to the relative speed between the emitter and the receiver of sound.
The expression for the Doppler effect of a moving source is
f ’= (v / (v- + v_s) f
From this expression we see that if the speed the sound source is different from zero feels a change in the frequency.
The correct answer is d
Answer: a) 6.67cm/s b) 1/2
Explanation:
According to law of conservation of momentum, the momentum of the bodies before collision is equal to the momentum of the bodies after collision. Since the second body was initially at rest this means the initial velocity of the body is "zero".
Let m1 and m2 be the masses of the bodies
u1 and u2 be their velocities respectively
m1 = 5.0g m2 = 10.0g u1 = 20.0cm/s u2 = 0cm/s
Since momentum = mass × velocity
The conservation of momentum of the body will be
m1u1 + m2u2 = (m1+m2)v
Note that the body will move with a common velocity (v) after collision which will serve as the velocity of each object after collision.
5(20) + 10(0) = (5+10)v
100 + 0 = 15v
v = 100/15
v = 6.67cm/s
Therefore the velocity of each object after the collision is 6.67cm/s
b) kinectic energy of the 10.0g object will be 1/2MV²
= 1/2×10×6.67²
= 222.44Joules
kinectic energy of the 5.0g object will be 1/2MV²
= 1/2×5×6.67²
= 222.44Joules
= 111.22Joules
Fraction of the initial kinetic transferred to the 10g object will be
111.22/222.44
= 1/2
