A 4.0 kg ball is traveling at 3.0 m/s and strikes a wall. The ball bounces off the wall with a velocity of 4.0 m/s in the opposi
1 answer:
You might be interested in
For the work-energy theorem, the work needed to stop the bus is equal to its variation of kinetic energy:
where
W is the work
Kf is the final kinetic energy of the bus
Ki is the initial kinetic energy of the bus
Since the bus comes at rest, its final kinetic energy is zero:
, so the work done by the brakes to stop the bus is
And the work done is negative, because the force applied by the brake is in the opposite direction to that of the bus motion.
where
W is the work
Kf is the final kinetic energy of the bus
Ki is the initial kinetic energy of the bus
Since the bus comes at rest, its final kinetic energy is zero:
And the work done is negative, because the force applied by the brake is in the opposite direction to that of the bus motion.
Answer:
Answer:
(a):
(b):
(c):
Explanation:
Given that an electron revolves around the hydrogen atom in a circular orbit of radius r = 0.053 nm = 0.053 m.
Part (a):
According to Coulomb's law, the magnitude of the electrostatic force of interaction between two charged particles of charges and
respectively is given by
where,
= Coulomb's constant =
= distance of separation between the charges.
For the given system,
The Hydrogen atom consists of a single proton, therefore, the charge on the Hydrogen atom,
The charge on the electron,
These two are separated by the distance,
Thus, the magnitude of the electrostatic force of attraction between the electron and the proton is given by
Part (b):
The gravitational force of attraction between two objects of masses and
respectively is given by
where,
= Universal Gravitational constant =
For the given system,
The mass of proton,
The mass of the electron,
Distance between the two,
Thus, the magnitude of the gravitational force of attraction between the electron and the proton is given by
The ratio :