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a_sh-v [17]
3 years ago
12

1) IT TAKES 10 PEOPLE TO PULL A 50 TON BUS.HOW MANY PEOPLE WOULDIT TAKE TO PULL A 100 TON BUS ?

Mathematics
1 answer:
Vanyuwa [196]3 years ago
4 0
1) The best thing to do here is to divide the two weights of the buses and fin out what you need to multiply it by. 
100/50= 2.
Therefore, you've got to multiply the amount of people by 2.
10*2= 20
Therefore, it takes 20 people to pull a 100 ton bus.

2) Here, you should work out what each one is worth. Half of 40 is 20.
one fourth of 20 is 5. Therefore, half of 40 is larger.

3) The best thing to do is to divide 32 by 8, and then multiply the number of degrees by this.
32/8=4
110*4= 440
Therefore, the ball rotates 440 degrees in 32 seconds.

4) the best thing to do is to find what one part is worth- and to do this, you have to add together the amount of roses and divide this by the total roses.
4+6= 10
50/10= 5
The roses are 6 parts yellow, therefore, 6*5= 30, there are 30 yellow roses.

Hope this helps :) 
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Please answer with explanation, I don't understand.<br><br> <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E2-14x%2B49%7D%20%3Dx
Crank

Answer: x ≥ 7

Step-by-step explanation:

You have to square both sides of the equation. You can manipulate an equation or function any way imaginable as long as it is done equally and helps the problem become easier. If we square this, the radical will cancel and we will get two trinomials equal to each other.

x^2-14x+49=(x-7)^2\\x^2-14x+49=x^2-14x+49

We can see the two expressions are exactly equal to each other. All real numbers are solutions, besides a few. These few are when the radical is equal to a negative number. So lets set up an inequality stating that the radical must be greater than or equal to 0.

x^2-14x+49\geq 0\\(x-7)^2 \geq 0\\x \geq 7

6 0
3 years ago
PLS HELP ITS TIMED!!!
Jlenok [28]

Answer:

it would be A

Step-by-step explanation:

6 0
3 years ago
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vivado [14]
9 because 9x4 equal 36
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3 years ago
What is the difference?
Len [333]

Answer:

D

Step-by-step explanation:

x/(x²+3x+2) - 1/[(x+2)(x+1)]

x² + 3x + 2 = x² + 2x + x + 2

= x(x + 2) + (x + 2)

= (x + 2)(x + 1)

= x/[(x+2)(x+1)] - 1/[(x+2)(x+1)]

= (x-1)/[(x+2)(x+1)]

= (x-1)/(x²+3x+2)

5 0
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6. In both Mr. Jacquez's Math 2 classes, Period 2 and Period 3 were given the same test. The table below shows the results from
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Answer: pass 12 fail 12 passes 15 fail1 3

Step-by-step explanation:

pass 12 fail 12

pass 15 fail 13

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