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sp2606 [1]
3 years ago
15

In Part 3.2.2 of the experiment, a pair of students measure θmirror = 19.5 degrees. To find θbench, they use the theoretical rel

ationship θmirror = 1/2 θbench. Then they measure θbench = 46.5 degrees. What is the discrepancy between theory and experiment for θbench?
Physics
1 answer:
KATRIN_1 [288]3 years ago
5 0

Answer:

discrepancy between theory and experiment 19.23 %

Explanation:

given data

Experimental theta (E) = 46.5 degrees

and

Theoretical theta (T) = 2 × 19.5 = 39 degree

so we can say % discrepancy will be

% discrepancy =  \frac{E-T}{T} * 100     .....................1

so

% discrepancy =  \frac{46.5-39}{39} * 100

% discrepancy = \frac{7.5}{39} * 100

% discrepancy = 19.23 %

so discrepancy between theory and experiment 19.23 %

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Answer:

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we substitute  

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Answer:

The equipment to use is: a beaker, a fixed amount of water, a thermometer.

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Explanation:

The design of an experiment is to place the beaker in the microwave, with a good amount of water (approximately ⅔ of its capacity) and turn it on for small periods of time, generally the minimum is 30 s, quickly open the microwave, place a thermometer or better yet an infrared thermometer to measure the temperature of the water; repeat this several times.

The advantage of the infrared thermometer is that it reduces the transfer of heat between the water and the thermometer.

The mass of water, the time, the temperature for each time should be noted and a graph of Temperature versus time should be made.

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