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3 years ago

6

sandra lives in a country located in the northern hemisphere she makes a sundial by erecting a pole vertically in her garden the

given figure shows the aerial view of the pole and the shadow it casts at 6:00 am on a summer day which of these figures shows the shadow of the same pole at 6:00 pm on the same day

1 answer:

Arte-miy333 [17]3 years ago

5 0

Answer:

C

Explanation:

The sun has rotated causing the shadow to reflect.

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the small electric shock you feel when you rub your shoes on carpet and touch something metal is caused by..?1. direct current2.

vovikov84 [41]

Answer:

1. direct current 2. induction 3. conduction

Explanation:

When we walk barefoot on a carpet there is friction between the carpet surface and the lower surface of the feet which results in the exchange of charges between the two surfaces. During this course the carpet loses electron to the surface of the foot. Now, the charge on the carpet is static because it is an insulator but a human body being a good conductor of electricity has mobility of the charges.(3)

These mobile charges on the surface of a human body spread and look for a path of dissipation to a reservoir. When we bring our hand near a metal it induces an opposite charge near the surface of the metal,(2) this happens within a fraction of seconds. Now there is a positive charge on the nearest point on the metal and the negative charge on its farthest end is induced according to the conservation of charges.

As soon as the hand touches the metal (1)there is a transfer of charge from our body to the metal generating a very small shock. This happens only if we continue to stand on an insulated surface due to which the charge doesn't gets transferred to the ground.

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3 years ago

Read 2 more answers

A 34-kg child runs with a speed of 2.8 m/s tangential to the rim of a stationary merrygo-round. The merry-go-round has a momentu

tekilochka [14]

Answer: $0.43\ rad/s$

Explanation:

Given

Mass of child $m=34\ kg$

speed of child is $v=2.8\ m/s$

Moment of inertia of merry go round is $I=510\ kg.m^2$

radius $r=2.31\ m$

Conserving the angular momentum

$\Rightarrow mvr=I\omega \\\Rightarrow 34\times 2.8\times 2.31=510\times \omega\\\\\Rightarrow \omega=\dfrac{219.912}{510}\\\Rightarrow \omega=0.43\ rad/s$

7 0

3 years ago

An object takes 2.8 years to orbit the Sun. What is its average distance (in AU) from the Sun?

Inessa05 [86]

answer look it up

Explanation:https://www.chegg.com/homework-help/questions-and-answers/takes-planet-28-years-orbit-sun-long-years-take-planet-go-way-around-sky-q29849397

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3 years ago

A transformer has two sets of coils, the primary with N1 = 160 turns and the secondary with N2 = 1400 turns. The input rms volta

vovikov84 [41]

To solve the problem it is necessary to apply the concepts related to the voltage in a coil, through the percentage relationship that exists between the voltage and the number of turns it has.

So things our data are given by

$N_1 = 160$

$N_2 = 1400$

$\Delta V_{1rms} = 62V$

PART A) Since it is a system in equilibrium the relationship between the two transformers would be given by

$\frac{N_1}{N_2} = \frac{\Delta V_{1rms}}{\Delta V_{2rms}}$

So the voltage for transformer 2 would be given by,

$\Delta V_{2rms} = \frac{N_2}{N_1} \Delta V_{1rms}$

PART B) To express the number value we proceed to replace with the previously given values, that is to say

$\Delta V_{2rms} = \frac{N_1}{N_2} \Delta V_{1rms}$

$\Delta V_{2rms} = \frac{1400}{160} 62V$

$\Delta V_{2rms} = 1446.66V$

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3 years ago

What is the energy in joules of a mole of photons associated with visible light of wavelength 486 nm?

Marrrta [24]

Answer:

$2.46\cdot 10^5 J$

Explanation:

The enegy of a single photon is given by:

$E=\frac{hc}{\lambda}$

where

h is the Planck costant

c is the speed of light

$\lambda$ is the wavelength of the photon

In this problem,

$\lambda=486 nm=4.86\cdot 10^{-7}m$

so the energy of one photon is

$E_1=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4.86\cdot 10^{-7}m}=4.09\cdot 10^{-19} J$

1 mole of photons contains a number of Avogadro of photons:

$N_A = 6.022\cdot 10^{23}$

therefore, the total energy of 1 mole of these photons will be

$E=N_A E_1 = (6.022\cdot 10^{23})(4.09\cdot 10^{-19} J)=2.46\cdot 10^5 J$

3 0

4 years ago