The average atomic weight is the average of weighted mass of a particular atom.
The weighted average mass of the atoms in a naturally occurring sample of an element is the average atomic mass, also known as atomic weight.
The average mass of an element's atoms expressed in atomic mass units is known as its atomic mass (amu, also known as daltons, D). The mass of each isotope is multiplied by its abundance to produce the atomic mass, which is a weighted average of all the isotopes of that element.
Therefore, the average atomic weight is the average of weighted mass of a particular atom.
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Answer: True the bicarbonate mixture can help save time and few routine.
Explanation:
For the purpose of making dialysate for hemodialysis patient therapies a bicarbonate mixing and delivering systems designed to prepare a liquid sodium bicarbonate formulation comes in handy.
Certain systems like the SDS unit also allow for the transfer and distribution of acid concentrate solutions. We also provide stand-alone acid concentrate delivery systems using a variety of holding tanks and delivery methods.
A challenge for hemodialysis providers is to properly provide bicarbonate solution in a cost effective manner. Preparation and disinfection can be time-consuming and labor intensive.
Bicarbonate however can corrode certain metals and painted surfaces leaving your preparation area encrusted and grimy.
Furthermore, if not mixed properly, bicarbonate can negatively affect the dialysate solution.
The answer to the above is true the bicarbonate mixture can help save time and few routine.
Answer:
Explanation:
When heat is supplied to a substance, the temperature of the substance increases according to:
where
Q is the amount of heat supplied
m is the mass of the substance
C is the specific heat capacity of the substance
is the initial temperature
is the final temperature
For the sample of magnesium in this problem, we have:
m = 63 g is the mass
Q = 6689 J is the hear supplied
C = 1.023 J/gC is the specific heat capacity
is the final temperature
Solving the formula for , we find the final temperature:
