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3 years ago

Can anyone help me please with this please

Chemistry

1 answer:

Ilya [14]3 years ago

3 0

Answer:

the source of energy for food is sunlight energy and the inside the cells of plants, algae, and photosynthetic bacteria, chlorophyll, and enzymes use the light energy to rearrange the atoms of the reactants to form the products. molecules of the glucose and oxygen gas

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3 years ago

NEED HELP ASAP!! MY BRAINLEST IS GIVING 50-100 POINTS!! NUMBER THEM 1-10!!

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1. A 2. C 3. A 4. B 5. C 6. A 7. B 8. A 9. C 10. B

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3 years ago

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Determine the end (final) value of n in a hydrogen atom transition, if the electron starts in and the atom emits a photon of lig

Usimov [2.4K]

Complete Question

Determine the end (final) value of n in a hydrogen atom transition, if the electron starts in n=4 and the atom emits a photon of light with a wavelength of 486 nm. Group of answer choices

Answer:

$n=2$

Explanation:

From the question we are told that:

Wavelength $\lambda=486nm=>486*10^{-9}$

Generally the equation for Atom Transition is mathematically given by

$\frac{1}{\lambda}=R_{\infty }(\frac{1}{n_1^2}-\frac{1}{n_2^2})$

Where

Rydberg constant $R_{\infty}=1.097*10^7$

Therefore

$\frac{1}{486*10^{-9}}=1.097*10^7*(\frac{1}{n_1^2}-\frac{1}{4^2})$

$(\frac{1}{n_1^2}-\frac{1}{4^2})=\frac{1}{486*10^{-9}*1.097*10^7}$

$n_1^2=3.98$

$n=1.99$

$n=2$

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3 years ago

Question 9 solid sodium chloride is produced by the reaction of chlorine gas and solid sodium . write a balanced chemical equati

alekssr [168]

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4 years ago

1. Determine the final volume of a 1.5 M HCl solution prepared from 20.0 mL

nadezda [96]

Explanation:

Because molarity is classified as moles of solute per liter of water, dilution of the water may result in a reduction of its concentration.

Therefore, because the amount of moles of solute has to be constant for dilution, you will use the molarity and volume of that same target solution to calculate how many moles of solute will be present in the sample of the stock solution that you dilute.

c = $\frac{n}{v}$