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adell [148]
3 years ago
9

Can anyone help me please with this please

Chemistry
1 answer:
Ilya [14]3 years ago
3 0

Answer:

the source of energy for food is sunlight energy and the inside the cells of plants, algae, and photosynthetic bacteria, chlorophyll, and enzymes use the light energy to rearrange the atoms of the reactants to form the products. molecules of the glucose and oxygen gas

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An unknown compound was decomposed into 63.2 g carbon, 5.26 g hydrogen, and 41.6 g oxygen. what is its empirical formula?
ira [324]
Step 1:
           Divide mass of each element with its M.mass in order to find out moles.

                       C  =  63.2 g / 12 g/mol  =  Moles  =  5.26 moles

                       H  =  5.26 g / 1.008 g/mol  =  Moles  =  5.21 moles

                       C  =  41.6 g / 16 g/mol  =  Moles  =  2.6 moles

Step 2:
          Select moles of the element with least value and divide all moles of element by it,
                             C                H             O          
                       5.26/2.6  :  5.21/2.6  :  2.6/2.6

                          2.02     :     2.00     :       1

Result:
               Empirical Formula  =     C₂H₂O
4 0
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What is found in the outer region of the electron cloud
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g A microwave oven heats by radiating food with microwave radiation, which is absorbed by the food and converted to heat. If the
Sliva [168]

Answer:

The total photons required = 5.19 × 10²⁸ photons

Explanation:

Given that:

the radiation wavelength λ= 12.5 cm = 0.125 m

Volume of the container = 0.250 L = 250 mL

The density of water = 1 g/mL

Density = mass /volume

Mass =  Volume ×  Density

Thus; the mass of the water =  250 mL ×  1 g/mL

the mass of the water = 250 g

the specific heat of water s = 4.18 J/g° C

the initial temperature T_1 = 20.0° C

the final temperature T_2 = 99° C

Change in temperature \Delta T = (99-20)° C = 79 ° C

The heat q absorbed during the process = ms \Delta T

The heat q absorbed during the process = 250 g × 4.18 J/g° C × 79° C

The heat q absorbed during the process = 82555 J

The energy of a photon can be represented by the equation :

= hc/λ

where;

h = planck's constant = 6.626 \times 10^{-34} \ J.s

c = velocity of light = 3.0 \times 10^8 \ m/s

=  \dfrac{6.626 \times 10^{-34} \times 3.0 \times 10^8}{0.125}

= 1.59024 \times 10^{-24} J

The total photons required = Total heat energy/ Energy of a photon

The total photons required = \dfrac{82555 J}{1.59024 \times 10^{-24}J}

The total photons required = 5.19 × 10²⁸ photons

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