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Allisa [31]
3 years ago
12

Please help I will mark Brainly!

Chemistry
1 answer:
IgorLugansk [536]3 years ago
6 0

It's NF3 (one Nitrogen and 3 Flouride)

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Which segement of the heating curve shown above represents an increase in the potential energy, but no change in the kinetic ene
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RS because it is moving but not a lot
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What will happen wen lead react with copper 2 sulfate​
dezoksy [38]

Answer:This is what's known as a metal displacement reaction: the lead substitutes for the copper and ends up precipitating out of solution as insoluble lead (II) sulfate. ... The weight of copper deposited was 15.86gm.

Explanation:

4 0
3 years ago
For the reaction N2(g) + O2(g)2NO(g) H° = 181 kJ and S° = 24.9 J/K G° would be negative at temperatures (above, below) K. Enter
12345 [234]

ΔG deg will be negative above 7.27e+3 K.

<u>Explanation:</u>

  • The ΔG deg with the temperature can be found using the formula and the formula is given below
  • ΔG deg = ΔH deg - T ΔS deg
  • Given data, ΔH deg = 181kJ and ΔSdeg=24.9J/K
  • -T ΔS deg will be always negative and ΔG deg = ΔH deg  will  be  positive and ΔG deg will be negative at relatively high temperatures and positive at relatively low temperatures
  • solving the equation and substitute  ΔGdeg=0
  • ΔGdeg = ΔHdeg - T ΔSdeg
  • T= ΔHdeg/ΔSdeg
  • T=181 kJ / 2.49e-2 kJK-1
  • By simplification we get
  • T=7.27 × 10^3 K.
  • Therefore, Go will be negative above   7.27 × 10^3 K
  • Since ΔG deg = -RT lnK, when ΔGdeg < 0, K > 1 so the reaction will have K > 1 above 7.27 × 10^3 K.
  • ΔG deg will be negative above 7.27e+3 K.

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7 0
3 years ago
A sample in the laboratory is found to contain 3.36 grams of hydrogen, 20.00 grams of carbon, and 26.64 grams of oxygen. The mol
KonstantinChe [14]

Answer:

Empirical formula is CH₂O.

Molecular formula = C₆H₁₂O₆

Explanation:

Given data:

Mass of hydrogen = 3.36 g

Mass of carbon = 20.00 g

Mass of oxygen = 26.64 g

Molar mass of compound = 180.156 g/mol

Empirical formula = ?

Molecular formula = ?

Solution:

Empirical formula:

It is the simplest formula gives the ratio of atoms of different elements in small whole number

Number of gram atoms of H = 3.36 / 1.01 = 3.3

Number of gram atoms of O = 26.64 / 16 = 1.7

Number of gram atoms of C = 20 / 12 = 1.7

Atomic ratio:

            C                      :        H            :         O

           1.7/1.7                :     3.3/1.7       :       1.7/1.7

              1                     :           2          :        1

C : H : O = 1 : 2 : 1

Empirical formula is CH₂O.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass = CH₂O = 12×1 + 2× + 16

Empirical formula mass = 30

n = 180.156 / 30

n = 6

Molecular formula = n (empirical formula)

Molecular formula = 6 (CH₂O)

Molecular formula = C₆H₁₂O₆

5 0
3 years ago
A compound composed of only C and H contains 79.88 % C by mass. What is its empirical formula?
Rufina [12.5K]

Answer:

a. CH3

Hope this helps.

3 0
3 years ago
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