During a total solar eclipse, the moon passes between Earth and the sun. This completely blocks out the sun’s light. However, the moon is about 400 times smaller than the sun. How can it block all of that light?
Answers:(a) 
μT
(b) 
μm
(c) f =
Explanation:Given electric field(in y direction) equation:

(a) The amplitude of electric field is

. Hence
The amplitude of magnetic field oscillations is

Where c = speed of light
Therefore,

μT (Where T is in seconds--signifies the oscillations)
(b) To find the wavelength use:



μm
(c) Since c = fλ
=> f = c/λ
Now plug-in the values
f = (3*10^8)/(0.4488*10^-6)
f =
Answer:
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When red light illuminates a grating with 7000 lines per centimeter, its second maximum is at 62.4°. What is the wavelength of this light?
ans: 633nm