A man punches his fist against a brick wall. Which will have a greater acceleration?

Difference between regular and irregular object.

DaniilM [7]

<h2>Answer:</h2><h2>Regular object</h2>

Those substance which have fixed geometrical shape are called regular object.
For example: books,pencils, basketball etc.

<h2>Irregular object</h2>

Those substance which do not have geometrical shape are called irregular object.
For example: a piece of stone,a broken piece of brick,leaf etc.

Hope this helps....

Good luck on your assignment.....

5 0

3 years ago

Young's experiment is performed with light of wavelength 502 nm from excited helium atoms. Fringes are measured carefully on a s

jok3333 [9.3K]

Answer:

0.88 mm

Explanation:

Given

Wavelength of the atoms, λ = 502 nm = 502*10^-9 m

Radius of the screen away from the double slit, r = 1 m

We know that Y(20) = 11.4*10^-3 m

d = (20 * R * λ) / Y(20)

d = (20 * 1 * 502*10^-9)/11.4*10^-3

d = 1*10^-5 / 11.4*10^-3

d = 0.88 mm

Therefore, the distance of separation between the two slits is 0.88 mm

7 0

4 years ago

The angle between the incident ray and the surface of a plane mirror is 20'. What is the total angle rotated by the incident ray

Dahasolnce [82]

Angle made by the light ray with the surface of mirror is given as

$\theta_i = 90 - 20 = 70$ degree

now as we know as per law of reflection that

angle of incidence = angle of reflection

So here we can say that

$\theta_i = \theta_r$

$\theta_r = 70 degree$

now the total angle that reflected ray will rotate with respect to incident ray is known as angle of deviation

$\delta =180 - \theta_i - \theta_r$

$\delta = 180 - 70 - 70 = 40 degree$

so here reflected light will deviate by total angle of 40 degree fron its incident ray.

7 0

4 years ago

The same strength force was exerted in the same direction on both Object A and Object B. Why did Object A go faster than Object

VashaNatasha [74]

Answer:

$m_B > m_A$

the mass of body B must be greater than the mass of body A

Explanation:

Newton's second law establishes a linear relationship between the force, the mass of the body and its acceleration

F = m a

a = F / m

Let's analyze this expression tells us that the force is of equal magnitude for the two bodies, but body A goes faster than body B, this implies that it has more relationships

a_A > a_B

$\frac{F}{m_A} > \frac{F}{m_B}$

$m_B > m_A$

Therefore, for this to happen, the mass of body B must be greater than the mass of body A

6 0

3 years ago

Pls help with either of these I will give up brainliest

Contact [7]

Answer:

1. The bird close to the center

2. 4/25 of the original force.

Explanation:

1. Tangential velocity is v=w*d (in m/s), where w is the rotational speed, commonly denoted as the letter omega (in radians per second). d is the distance from the center of the rotating object to the position of where you would like to calculate the velocity (in meters).

As we can note, the furthest from the center we are calculating the velovity the higher it is, because the rotational velocity is not changing but the distance of the object with respect to the center is. If v=w*d, then the lower the d (distance) the lower the tangential velocity.

2. Take a look at the picture:

We have the basic equation for the gravitational force.

We have to forces: Fg1, which is the original force, and Fg2, the force when the mass and the distance changes.

If we consider that mass 2 didn't change (m2'=m2), mass 1 is four times its original (m1'=4*m1) and distance is 5 times the original (r'=5*r), then next step is just plugging it into the equation for Fg2.

Dividing the original force Fg1 by the new force Fg2 (notice you can just as well do the inverse, Fg2 divided by Fg1) gives us the relation between the forces, cancelling all the variables and being left only with a simple fraction!

6 0

3 years ago