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Arturiano [62]
3 years ago
15

How many elements does the periodic table have quick my wifi not working help please

Chemistry
1 answer:
dlinn [17]3 years ago
3 0
There is 118 elements<span> in the periodic table</span>
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In order for oxygen gas, nitrogen gas, and carbon dioxide to have the same volume, they must have the same ______. (Check all an
musickatia [10]
The volume of a gas can be found by using ideal gas formula. The formula would be:

V= nRT/P
where
n= number of the molecule (mol)
R= constant
T= temperature
P= pressure

Then, the answer would be 
<span>1. temperature
2. pressure
3. mass
4. number of molecules </span>
7 0
3 years ago
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Explanation:

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3 years ago
What is the theoretical yield of so3 produced by the quantities described in part a? express your answer numerically in grams?
PSYCHO15rus [73]
Sulfur reacts with oxygen to yield SO3 as shown in the equation below;
 2S(g)+ 3O2(g) = 2SO3(g)
From part A 7.49 g of S were used.
The atomic mass of sulfur is 32.06 g/mol
Hence, the number of moles of sulfur used
 7.49 / 32.06 = 0.2336 moles
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8 0
3 years ago
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MakcuM [25]
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Consider the intermediate chemical reactions. 2 equations. First: upper C a (s) plus upper C upper O subscript 2 (g) plus one ha
DochEvi [55]

<u>Answer:</u> When the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation is halved and has its sign changed.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The overall chemical reaction follows:

CaO(s)+CO_2\rightarrow CaCO_3(s)     \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) Ca(s)+CO_2(g)+\frac{1}{2}O_2(g)\rightarrow CaCO_3(s)    \Delta H_1=-812.8kJ  

(2) 2Ca(s)+O_2(g)\rightarrow 2CaO(s)     \Delta H_2=-1269kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[\frac{1}{2}\times (-\Delta H_2)]

Hence, when the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation is halved and has its sign changed.

3 0
3 years ago
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