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DochEvi [55]
3 years ago
11

The mineral stibnite, antimony(III) sulfide, is treated with hydrochloric acid to give antimony(III) chloride and hydrogen sulfi

de gas.
Part A
What mass of SbCl3 is produced from a 2.85 g sample of stibnite?
Chemistry
1 answer:
jeka943 years ago
5 0
The balanced chemical reaction is written as:

Sb2S3 + 6HCl = 6SbCl<span>3 + 3H2S

We are given the amount of </span><span>antimony(III) sulfide to be used in the reaction. This is amount will be used for the calculations. We do as follows:

2.85 g Sb2S3  ( 1 mol / </span><span>339.715 g ) ( 6 mol SbCl3 / 1 mol Sb2S3 ) (</span> 228.13 g / mol ) = 11.48 g SbCl3
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Solution is the answer.
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3 years ago
PLEASE HELP QUICK!! WILL MARK BRAINLIEST ANSWER!! When water is diffused across a selectively permeable membrane, scientists ref
xxTIMURxx [149]

Answer :

During diffusion, when the concentration of the molecules on both sides of the membrane is the same, the molecules will continue to move across the membrane in both the direction.

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Answer 4: The nucleus is an organelle that is surrounded by the cytoplasm, a jelly-like fluid.

Explanation :

Diffusion : It is a process where liquid moves from higher concentration to the lower concentration through permeable membrane.

When the concentration of the molecules on both sides of the membrane is same and the membrane is permeable membrane then diffusion will occur and the molecules will moves continuously across the membrane in both the direction.

Answer 3 :

Mitosis : It is a process of cell division. In this process, nucleus divides into two daughter cell and each daughter cell contains same number of chromosomes as present in parent nucleus.

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Answer 4 :

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7 0
2 years ago
Consider the formula al2(so4)3. how many atoms of aluminum are present?
Shkiper50 [21]
2 atoms of aluminium
3 0
3 years ago
How many moles are in 20 grams of O₂ gas?
Dima020 [189]
20 g O2 x 1 mol O2/32 g O = 0.625 mol O2
4 0
2 years ago
Realiza los cálculos para determinar la cantidad de KOH 90%, que se necesita para preparar 100 ml de solución 1N.
attashe74 [19]

Answer:

6.23 KOH 90% son necesarios

Explanation:

Una solución 1N de KOH requiere 1equivalente (En KOH, 1eq = 1mol) por cada litro de solución.

Para responder esta pregunta se requiere hallar los equivalentes = Moles de KOH para preparar 100mL = 0.100L de una solución 1N. Haciendo uso de la masa molar de KOH y del porcentaje de pureza del KOH se pueden calcular los gramos requeridos para preparar la solución así:

<em>Equivalentes KOH:</em>

0.100L * (1eq / L) = 0.100eq = 0.100moles

<em>Gramos KOH -Masa molar: 56.1056g/mol-:</em>

0.100moles * (56.1056g/mol) = 5.61 KOH se requieren

<em>KOH 90%:</em>

5.61g KOH * (100g KOH 90% / 90g KOH) =

<h3>6.23 KOH 90% son necesarios</h3>
8 0
2 years ago
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