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Liula [17]
3 years ago
13

Which process is a physical change? iron rusting milk turning into curd water boiling paper burning hard water stains pipes?

Chemistry
2 answers:
Elodia [21]3 years ago
6 0
Iron rusting over is a physical change.
Len [333]3 years ago
5 0

Answer: Option (c) is the correct answer.

Explanation:

A change that causes no change in chemical composition of a substance is known as a physical change.

For example, boiling of water is a physical change as state of water is changing from liquid to vapors.

On the other hand, a change that causes a change in chemical composition of a substance is known as a chemical change.

For example, rusting of iron, churning of milk into curd, burning of paper, stains of hard water on pipes are all chemical changes.

Thus, we can conclude that water boiling process is a physical change.

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castortr0y [4]

Answer:

pOH= 11

Explanation:

pOH= -log[10^ -11]= 11

7 0
3 years ago
Combustion of methanol displayed formula???
Andrew [12]

Answer:

reee, here is your answer.

Explanation: CH3OH(l) + 3O2(g) rightarrow CO2(g) + 3H2O(g) CH3OH(l) + O2(g) rightarrow CO2(g) + 2H20(g) CH3OH(l) + 2O2(g) rightarrow 2CO2(g) + 4H20(g) 2CH3OH(l) + 3O2(g) rightarrow 2CO2(g) + 4H20(g) Correct Calculate Delta H degree rxn at 25 degree C.

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3 years ago
What is the percent composition of iron in FeCl3​
ololo11 [35]

calculate the molar mass of Fe + 3(Cl)

that is your total mass

percent composition of FeCl3

mass % Fe = molar mass FE / total mass X 100 = %

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Hope it’s help !!!!

7 0
3 years ago
Which statement describes the number of protons in each atom of an element? (1 point)
Ierofanga [76]

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B.

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8 0
2 years ago
A total of 620 C of charge passes through a flashlight in 0.510 h. What is the average current in milliamperes?
aniked [119]

Explanation:

The given data is as follows.

               Q = 620 C,         t = 0.510 hour

First, we will convert hours into seconds. Since, there are 3600 seconds present in 1 hour. Hence, number of seconds present in 0.510 hour are as follows.

                   0.510 hr \times \frac{3600 sec}{1 hr}

                     = 1836 sec

Therefore, we will calculate the average current as follows.

                      I = \frac{Q}{t}

                        = \frac{620 C}{1836 sec}

                        = 0.337 C/sec

It is known that,

                      1 C/sec = 1000 mA

So,             0.337 C/sec \times \frac{1000 mA}{1 C/s}

                    = 337 mA

Thus, we can conclude that the average current in milliamperes is 337 mA.

4 0
3 years ago
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