Answer: B. thermocouple measures temperatures at the tip and the thermistor at the dimple.
Explanation:
A thermistor is a temperature-sensitive resistor, whilst a thermocouple generates a voltage proportional to the temperature. Thermocouples can work at much higher temperatures than thermistors. They are commonly used for temperature control in heating systems.
True
the answer to this would be true
Answer: 98.5% of pearlite was formed during the equilibrium cooling
Explanation:
First we calculate the fraction of pro-eutectoid phase which forms for equilibrium cooling of the 1085 steel from 1000°C at room temperature;
we know that in 1085 steel, last two digits denotes the carbon percentage
so 1085 steel contains 0.85% carbon.
Now from the diagram, carbon percentage is greater than the eutectoid com[psition
i.e 0.85 > 0.76
it is a hyper eutectoid steel
so
fraction of pro eutectoid phase W_Fe₃C = (0.85 - 0.76) / ( 6.7 - 0.76)
= 0.09 / 5.94 = 0.015 = 1.5%
Now, the amount of pearlite formed during the equilibrium cooling of the 1055 steel from 1000°C to room temperature will be;
pearlite (C') = (1 - W_Fe₃C)
= 1 - 0.015
= 0.985 = 98.5%
Therefore 98.5% of pearlite was formed during the equilibrium cooling
Answer:
-4.6431 kW
Explanation:
Given parameters:
kg/s
kJ/kg·K
° C
Let the work done on the fan be = -300 W = -0.3 kW
Let the heat loss by air from the duct be = -300W = -0.3 kW
We are asked to find the power rating of the electric resistance heating element,
Energy-Balance equation for the system is:
kW
Here, (-) sign means work done on the system.