Answer:
1561.84 MPa
Explanation:
L=20 cm
d1=0.21 cm
d2=0.25 cm
F=5500 N
a) σ= F/A1= 5000/(π/4×(0.0025)^2)= 1018.5916 MPa
lateral strain= Δd/d1= (0.0021-0.0025)/0.0025= -0.16
longitudinal strain (ε_l)= -lateral strain/ν = -(-0.16)/0.3
(assuming a poisson's ration of 0.3)
ε_l =0.16/0.3 = 0.5333
b) σ_true= σ(1+ ε_l)= 1018.5916( 1+0.5333)
σ_true = 1561.84 MPa
ε_true = ln( 1+ε_l)= ln(1+0.5333)
ε_true= 0.4274222
The engineering stress on the rod when it is loaded with a 5500 N weight is 1561.84 MPa.
Answer:
#include <stdio.h>
typedef struct InventoryTag_struct {
int itemID;
int quantityRemaining;
} InventoryTag;
int main(void) {
InventoryTag redSweater;
redSweater.itemID = 314;
redSweater.quantityRemaining = 500;
/* Your solution goes here */
printf("Inventory ID: %d, Qty: %d\n",redSweater.itemID,redSweater.quantityRemaining);
getchar();
return 0;
}
Explanation:
Answer:
Go to explaination for the details of the answer.
Explanation:
Angle of friction (friction angle) is a measure of the ability of a unit of rock or soil to withstand a shear stress. It is the angle (φ), measured between the normal force (N) and resultant force (R), that is attained when failure just occurs in response to a shearing stress (S).
The cohesion intercept is a used when we want to describe the shear strength soils. The definition is mainly derived from the Mohr-Coulomb failure criterion and it is used to describe the non-frictional part of the shear resistance which is independent of the normal stress.
Please check attachment to Determine the friction angle and cohesion intercept.