Newton’s second law: F=ma. 2500=1000a. a=2.5m/s*s. Final velocity is 2.5*30=75m/s. Average speed is (Vi+Vf)/2, which is 37.5m/s. D=vt. 37.5*30=1125m. The distance traveled is 1125 meters
Answer:
the speed that have 0.0100 kilogram bullet with the similar momentum magnitude is 360 m/s
Explanation:
The computation of the speed that have 0.0100 kilogram bullet with the similar momentum magnitude is as follows:
The ball momentum is

As there is a similar momentum
So,

Hence, the speed that have 0.0100 kilogram bullet with the similar momentum magnitude is 360 m/s
The answer is D I’m not really sure yet
Answer:
Angle of reflection is also 65 degrees
Explanation:
angle of incidence = angle of reflection
I’m pretty sure you times them so 1 with A, 2 with e, 3 with C, and 4 with B