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elena55 [62]
3 years ago
8

Calculating Displacement from the Area under a Curve Try Use the graph to answer the question What is the total displacement of

the object after 5 seconds? Velocity vs. Time m 70 Velocity (m/s) 60 50 40 30 20 10 0 0 1 2 3 4 5 Time (s) Done Intro 15 of 18​

Physics
1 answer:
Agata [3.3K]3 years ago
8 0

Answer:

175 m

Explanation:

In a velocity vs time graph, displacement is the area under the curve.

We can calculate this as area of a trapezoid:

A = ½ (10 m/s + 60 m/s) (5 s)

A = 175 m

Or, we can split the area into a rectangle and a triangle.

A = (10 m/s) (5 s) + ½ (60 m/s − 10 m/s) (5 s)

A = 175 m

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3 years ago
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Light in the air is incident at an angle to the surface of (12.0 A) degrees on a piece of glass with an index of refraction of (
Orlov [11]

The question is incomplete. You dis not provide values for A and B. Here is the complete question

Light in the air is incident at an angle to a surface of (12.0 + A) degrees on a piece of glass with an index of refraction of (1.10 + (B/100)). What is the angle between the surface and the light ray once in the glass? Give your answer in degrees and rounded to three significant figures.

A = 12

B = 18

Answer:

18.5⁰

Explanation:

Angle of incidence i = 12.0 + A

A = 12

= 12.0 + 12

= 14

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= 1.10 + 18/100

= 1.10 + 0.18

= 1.28

We then find the angle of refraction index u

u = sine i / sin r

u = sine24/sinr

1.28 = sine 24 / sine r

1.28Sine r = sin24

1.28 sine r = 0.4067

Sine r = 0.4067/1.28

r = sine^-1(0.317)

r = 18.481

= 18.5⁰

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2 years ago
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Hope this helps, if you need clarification i got you

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