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iVinArrow [24]
2 years ago
9

Define potential difference as used in electricity​

Physics
2 answers:
lord [1]2 years ago
7 0

the diffrence in potential betwen two points that represents the work involved or the energy relesed in the transfe of <em>a </em><em>unit quantity of electicity from one point to the other </em>

ELEN [110]2 years ago
3 0

Answer:

Explanation:

Testing answer please do not delete

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A driver looks at her dashboard and reads that she is traveling at 100 kilometers per hour. What does this measurement represent
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The answer is C!! 100 kilometers per hour is an average speed.
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A motorcycle is traveling east at a rate of 56mph.it take 6.7 s for it to decrease its speed to 35mph. How far does the motorcyc
Phantasy [73]
Initial speed = 56mph
Final speed = 35mph

Time taken = 6.7seconds...

Converting the time to hour.. Divide by 3600..
= 6.7/3600

=0.00186hour..

Acceleration = v-u/t

a = 35-56/0.00186
a = -11283.6mph²

The negative sign shows that it decelerated...

V² = u²+2as

(35)² = (56)² + 2×-11283.6×s
Where s is the distance covered within that time...

1225 = 3136 - 22567.2s

22567.2s = 3136-1225

22567.2s = 1911

S = 1911/22567.2

S = 0.08468miles...

But at the end of the question we were made to understand that 1miles = 5280ft

Therefore 0.08468miles = (0.08468×5280)ft

= 447. 11feets...

Which is approximately 447ft.....


Hope this helped.... ?
8 0
3 years ago
Anna Litical is practicing a centripetal force demonstration at home. She fills a bucket with water, ties it to a strong rope, a
dlinn [17]

Answer:

Explanation:

Suppose when bucket is half full it has a mass of 2 m rotating in a circle of  radius r

When Bucket is quarter full then it has a mass of m rotating in a circle of radius r.

When an object moves in a circular path then it experiences an inward force which is given by

F_1=\frac{2mv^2}{r}

where v=velocity of bucket

Force in case 2 is given by

F_2=\frac{mv^2}{r}

Thus F_1=2F_2

therefore force required in half bucket is more than force required in quarter bucket full.

6 0
3 years ago
As light shines from air to another medium, i = 30.0o, the light bends toward the normal and refracts at 22.0o. What is the inde
iVinArrow [24]
The answer is n = 1.3347
7 0
3 years ago
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A certain freely falling object, released from rest, requires 1.95 s to travel the last 23.5 m before it hits the ground. (a) Fi
Ratling [72]

Answer:

(a). The velocity of the object is -2.496 m/s.

(b).  The total distance of the object travels during the fall is 23.80 m.

Explanation:

Given that,

Time = 1.95 s

Distance = 23.5 m

(a). We need to calculate the velocity

Using equation of motion

s = ut+\dfrac{1}{2}gt^2

Put  the value into the formula

-23.5=u\times1.95+\dfrac{1}{2}\times(-9.8)\times(1.95)^2

u=\dfrac{-23.5+4.9\times(1.95)^2}{1.95}

u=-2.496\ m/s

(b). We need to calculate the total distance the object travels during the fall

Using equation of motion

v = u+gt

Put the value in the equation

-2.496=0-9.8\times t

t =\dfrac{2.496}{9.8}

t=0.254\ sec

The total time is

t'=t+1.95

t'=0.254+1.95

t'=2.204\ sec

We need to calculate the distance

Using equation of motion

s = ut+\dfrac{1}{2}gt^2

Put the value into the formula

s=0+\dfrac{1}{2}\times9.8\times(2.204)^2

s=23.80\ m

Hence, (a). The velocity of the object is -2.496 m/s.

(b).  The total distance of the object travels during the fall is 23.80 m.

4 0
3 years ago
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