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3 years ago

Convert 205 L to ul.

Chemistry

2 answers:

Sloan [31]3 years ago

8 0

Answer: 205000000 microliter

Hope this helps!

Vinil7 [7]3 years ago

7 0

Answer:

2.05 x 10⁸ uL

205000000 uL

Explanation:

Step 1: Find the conversion

1 liter (L) = 1 x 10⁶ microliters (uL)

Step 2: Set up dimensional analysis

$205 L(\frac{1(10)^6uL}{1L} )$

Step 3: Multiply and cancel out units

Liters and Liter cancel out.

We are left with uL

205(1 x 10⁶) = 2.05 x 10⁸ uL or 205000000 uL

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A chemist measures the amount of fluorine gas produced during an experiment. He finds that 482. g of fluorine gas is produced.

nata0808 [166]

Answer: 25.37055324733817mol

Approximately 25.371mol

Explanation: Number of moles of a substance is the mass of that substance containing the same amount of fundamental units, for instance atom in 12.0g of 12°C

Therefore:

Number of moles= mass/ molecular mass

Where mass of fluorine given= 482g

Standard Molecular mass of fluorine= 18.9984032g/mol

Substituting value in equation

Mole= 482g/18.9984032g/mol = 25.37055324733817mol

Approximately : 25.371mol

4 0

2 years ago

If the symbol X represents a central atom, Y represents outer atoms, and Z represents lone pairs on the central atom, the struct

Snowcat [4.5K]

Answer:

XY4Z2 ----- square planar

XY5Z ------- square pyramidal

XY2Z----- bent < 120°

XY2Z3 ----- Linear

XY4Z ---- see saw

XY2Z2 ----- bent <109°

XY3Z2 ----- T shaped

XY3Z ----- Trigonal pyramidal

Explanation:

The valence shell electron pair repulsion theory ( VSEPR) gives the description of molecular geometry based on the relative number of electron pairs present in the molecule.

However, electron pairs repel each other, the repulsion between two lone pairs is greater than the repulsion between a lone pair and a bond pair which is also greater than the repulsion between two lone pairs.

The presence of lone pairs distort the bond angle and molecular geometry from the expected geometry based on VSEPR theory. Hence, in the presence of lone pairs of electron, the observed molecular geometry may be different from that predicted on the basis of the VSEPR theory, the bond angles also differ slightly or widely depending on the number of lone pairs present.

All the molecules in the question possess lone pairs, the number of electron pairs do not correspond to the observed molecular shape or geometry due to lone pair repulsion. Usually, the molecular geometry deals more with the arrangement of bonded atoms in the molecule.

8 0

3 years ago

THURSDAY Mr. Pate's science class performed an experiment involving the chemical reaction of sodium bicarbonate (baking soda) an

Kitty [74]

The balloon will burst if the volume of the balloon is less than 1.68 L since 8 g of sodium bicarbonate produces 1.68 L of carbon dioxide gas.

<h3>What is the volume of carbin dioxude produced from the chemical reaction between sodium bicarbonate (baking soda) and vinegar?</h3>

The volume of carbon dioxide produced is obtained from the equation below:

$CH_3COOH + NaCO_3 \rightarrow CH_3COONa + H_2O + CO_2 \\$

1 mole of sodium bicarbonate reacts with one mole of acetic acid in vinegar to produce 1 mole of carbon dioxide.

The volume of 1 mole of carbon dioxide is 22.4 L

Moles of sodium bicarbonate in 8 g = mass/molar mass

molar mass of sodium bicarbonate = 106 g

moles of sodium bicarbonate = 8/106 = 0.075 moles

Moles of carbon dioxide produced = 0.075 moles

Volume of carbon dioxide = 0.075 × 22.4 = 1.68 L

Therefore, the balloon will burst if the volume of the balloon is less than 1.68 L.

Learn more about gas volume at: brainly.com/question/24263739

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7 0

1 year ago

Please help ASAP!

nadezda [96]

nuetron, a neutron has no charge.

5 0

3 years ago

Enter your answer in the provided box. The usefulness of radiocarbon dating is limited to objects no older than 50,000 yr. What

guapka [62]

Answer : The percent of the carbon−14 left is, 0.242 %

Explanation :

This is a type of radioactive decay and all radioactive decays follow first order kinetics.

To calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{5.73\times 10^3\text{ years}}$

$k=1.205\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the amount left.

Expression for rate law for first order kinetics is given by :

$k=\frac{2.303}{t}\log\frac{a}{a-x}$

where,

k = rate constant = $1.205\times 10^{-4}\text{ years}^{-1}$

t = time taken for decay process = 50000 years

a = initial amount or moles of the reactant = 7 g

a - x = amount or moles left after decay process = ?

Putting values in above equation, we get:

$1.205\times 10^{-4}=\frac{2.303}{50000\text{ years}}\log\frac{7g}{a-x}$

$a-x=0.0169g$

The amount left of carbon-14 = 0.0169 g

Now we have to calculate the percent of the carbon−14 left.

$\text{Percent of carbon}-14\text{ left}=\frac{\text{Amount left of carbon}-14}{\text{Original amount of carbon}-14}\times 100$

$\text{Percent of carbon}-14\text{ left}=\frac{0.0169g}{7g}\times 100=0.242\%$

Therefore, the percent of the carbon−14 left is, 0.242 %

8 0

2 years ago