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ziro4ka [17]
3 years ago
9

3. How many grams are in 9.015 x 1035 atoms of Cobalt?​

Chemistry
1 answer:
pentagon [3]3 years ago
3 0

Answer:

8.822 × 10¹³ g Co

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

9.015 × 10³⁵ atoms Co

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Co - 58.93 g/mol

<u>Step 3: Convert</u>

<u />9.015 \cdot 10^{35} \ atoms \ Co(\frac{1 \ mol \ Co}{6.022 \cdot 10^{23} \ atoms \ Co} )(\frac{58.93 \ g \ Co}{1 \ mol \ Co} ) = 8.82189 × 10¹³ g Co

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

8.82189 × 10¹³ g Co ≈ 8.822 × 10¹³ g Co

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