It’s hard which class are u
Answer:
Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu
Explanation:
- Copper (I) nitrate = CuNO₃ (Nitrate, NO₃⁻, always has a charge of -1).
- Iron (III) nitrate = Fe(NO₃)₃ (That way the compound has an overall neutral charge)
Writing the equation using symbols leaves us with:
- Fe + CuNO₃ → Fe(NO₃)₃ + Cu
<em>It is not balanced yet</em>. Now we <u>balance the NO₃ species on the left side</u>:
- Fe + 3CuNO₃ → Fe(NO₃)₃ + Cu
Finally we<u> balance the Cu species on the right side</u>:
- Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu
Answer:
N₂+3H₂ ⇄2NH₃ is a thermochemical reaction whereas A+BC⇄AB is not.
A+BC⇄AB is a reaction of pure a element with a compound while N₂+3H₂ ⇄2NH₃ is a reaction between two pure elements.
Explanation:
Let A+BC⇄AB be equation i and N₂+3H₂ ⇄2NH₃ be equation ii.
The two reactions differ in that ii is a thermo-chemical reaction whereas i is not. This is because energy is included in reaction ii but not included in reaction i.
Also i is a reaction of pure a element with a compound while ii is a reaction between two pure elements. The compound is BC while the pure element is A.
Answer : The number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams
Solution : Given,
Volume of solution = 500 ml
Molarity of KOH solution = 0.189 M
Molar mass of KOH = 56 g/mole
Formula used :
Now put all the given values in this formula, we get the mass of solute KOH.
Therefore, the number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams
I believe it’s answer B because even in space gravity plays roles.
