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luda_lava [24]
3 years ago
12

Which of the following will increase polymer strain to failure

Chemistry
1 answer:
Blizzard [7]3 years ago
4 0

increase Polymer strain to failure is given below.

Explanation:

  • Strain to failure gives the measure of how much the specimen is elongated to failure. By this it means that, it you have strain to failure of 3% measured in specimen of length 100 mm, the material will fail when it it elongated 3 mm, as experimented in tensile test. Therefore, for a material with higher strain to failure rate, the ductility is higher and tensile strength is lower.

  • Tensile strength means the maximum mechanical stress (i.e. applied force divided by (initial) cross-section area of the specimen tested) during a tensile test, which is not directly correlated to the deformability or strain at failure or break since the tensile strength also is affected by the stiffness of the material. Therefore a ductile material might deform on a lower mechanical stress level than a stiffer one (this is the usual case), meaning its tensile strength is lower although its deformability is higher.
  • Therefore, for a material with higher strain to failure rate, the ductility is higher and tensile strength is lower.

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Write the lewis structure for mgi2. draw the lewis dot structure for mgi2. include all lone pairs of electrons.
viktelen [127]
Lewis Structure is drawn in following steps,

1) Calculate Number of Valence Electrons:
    
# of Valence electrons in Mg  =  2
# of Valence electrons in I      =  7
# of Valence electrons in I      =  7
                                               ---------
Total Valence electrons          =  16

2) Draw Mg as a central atom surround it by two atoms of Iodine.

3) Connect each Iodine atom to Mg, and subtract two electrons per bond. In this case we will subtract 4 electrons from total valence electrons. i.e.

Total Valence electrons           16
- Four electrons                    -   4
                                              ----------
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4) Now start adding the remaining 12 electrons on more electronegative atoms i.e. Iodine.

The final lewis structure formed is as follow, 

4 0
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