All categories

3 years ago

Which of the following will increase polymer strain to failure

Chemistry

1 answer:

Blizzard [7]3 years ago

4 0

increase Polymer strain to failure is given below.

Explanation:

Strain to failure gives the measure of how much the specimen is elongated to failure. By this it means that, it you have strain to failure of 3% measured in specimen of length 100 mm, the material will fail when it it elongated 3 mm, as experimented in tensile test. Therefore, for a material with higher strain to failure rate, the ductility is higher and tensile strength is lower.

Tensile strength means the maximum mechanical stress (i.e. applied force divided by (initial) cross-section area of the specimen tested) during a tensile test, which is not directly correlated to the deformability or strain at failure or break since the tensile strength also is affected by the stiffness of the material. Therefore a ductile material might deform on a lower mechanical stress level than a stiffer one (this is the usual case), meaning its tensile strength is lower although its deformability is higher.

Therefore, for a material with higher strain to failure rate, the ductility is higher and tensile strength is lower.

You might be interested in

I need these done please

valkas [14]

Answer:

A, it is metal oxide

8 0

2 years ago

Read 2 more answers

Does this sound catchy or invite you to read more? "GMOs and pesticides are general amongst farmers for generations and should n

siniylev [52]

Answer:

It sounds fine, but it may be a bit too long. It's difficult to shorten things like this, but getting more straight to the point would give it that "catchy" feel.

Explanation:

3 0

2 years ago

10 What is a characteristic of all living organisms?

Vladimir [108]

Answer:

D - ingestion

Explanation:

7 0

2 years ago

Read 2 more answers

When Aluminum oxide is heated with iron no reaction takes place?

Keith_Richards [23]

Answer:

Explanation:

That's correct. Once Aluminum becomes an ion, it is very hard to force it to take back its electrons. Only a few elements can do it. Iron is not one of them.

7 0

2 years ago

Two solutions namely, 500 ml of 0.50 m hcl and 500 ml of 0.50 m naoh at the same temperature of 21.6 are mixed in a constant-pre

weeeeeb [17]

24.6 ℃

<h3>Explanation</h3>

Hydrochloric acid and sodium hydroxide reacts by the following equation:

$\text{HCl} \; (aq) + \text{NaOH} \; (aq) \to \text{NaCl} \; (aq) + \text{H}_2\text{O} \; (aq)$

which is equivalent to

$\text{H}^{+} \; (aq) + \text{OH}^{-} \; (aq) \to \text{H}_2\text{O}\; (l)$

The question states that the second equation has an enthalpy, or "heat", of neutralization of $-56.2 \; \text{kJ}$ . Thus the combination of every mole of hydrogen ions and hydroxide ions in solution would produce $56.2 \; \text{kJ}$ or $56.2 \times 10^{3}\; \text{J}$ of energy.

500 milliliter of a 0.50 mol per liter "M" solution contains 0.25 moles of the solute. There are thus 0.25 moles of hydrogen ions and hydroxide ions in the two 0.500 milliliter solutions, respectively. They would combine to release $0.25 \times 56.2 \times 10^{3} = 1.405 \times 10^{4} \; \text{J}$ of energy.

Both the solution and the calorimeter absorb energy released in this neutralization reaction. Their temperature change is dependent on the heat capacity <em>C</em> of the two objects, combined.

The question has given the heat capacity of the calorimeter directly.

The heat capacity (the one without mass in the unit) of water is to be calculated from its mass and <em>specific</em> heat.

The calorimeter contains 1.00 liters or $1.00 \times 10^{3} \; \text{ml}$ of the 1.0 gram per milliliter solution. Accordingly, it would have a mass of $1.00 \times 10^{3} \; \text{g}$ .

The solution has a specific heat of $4.184 \; \text{J} \cdot \text{g}^{-1} \cdot \text{K}^{-1}$ . The solution thus have a heat capacity of $4.184 \times 1.00 \times 10^{3} = 4.184 \times 10^{3} \; \text{J} \cdot\text{K}^{-1}$ . Note that one degree Kelvins K is equivalent to one degree celsius ℃ in temperature change measurements.

The calorimeter-solution system thus has a heat capacity of $4.634 \times 10^{3} \; \text{J} \cdot \text{K}^{-1}$ , meaning that its temperature would rise by 1 degree celsius on the absorption of 4.634 × 10³ joules of energy. $1.405 \times 10^{4} \; \text{J}$ are available from the reaction. Thus, the temperature of the system shall have risen by 3.03 degrees celsius to 24.6 degrees celsius by the end of the reaction.

4 0

2 years ago