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luda_lava [24]
3 years ago
12

Which of the following will increase polymer strain to failure

Chemistry
1 answer:
Blizzard [7]3 years ago
4 0

increase Polymer strain to failure is given below.

Explanation:

  • Strain to failure gives the measure of how much the specimen is elongated to failure. By this it means that, it you have strain to failure of 3% measured in specimen of length 100 mm, the material will fail when it it elongated 3 mm, as experimented in tensile test. Therefore, for a material with higher strain to failure rate, the ductility is higher and tensile strength is lower.

  • Tensile strength means the maximum mechanical stress (i.e. applied force divided by (initial) cross-section area of the specimen tested) during a tensile test, which is not directly correlated to the deformability or strain at failure or break since the tensile strength also is affected by the stiffness of the material. Therefore a ductile material might deform on a lower mechanical stress level than a stiffer one (this is the usual case), meaning its tensile strength is lower although its deformability is higher.
  • Therefore, for a material with higher strain to failure rate, the ductility is higher and tensile strength is lower.

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What is the smallest division on this balance?
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0.001 would be the smallest.

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4 0
3 years ago
Read 2 more answers
Practice Problem: True Stress and Strain A cylindrical specimen of a metal alloy 49.7 mm long and 9.72 mm in diameter is stresse
amm1812

Answer:

The true stress required = 379 MPa

Explanation:

True Stress is the ratio of the internal resistive force to the instantaneous cross-sectional area of the specimen. True Strain is the natural log to the extended length after which load applied to the original length. The cold working stress – strain curve relation is as follows,

σ(t) = K (ε(t))ⁿ, σ(t) is the true stress, ε(t) is the true strain, K is the strength coefficient and n is the strain hardening exponent

True strain is given  by

Epsilon t =㏑ (l/l₀)

Substitute㏑(l/l₀) for ε(t)

σ(t) = K(㏑(l/l₀))ⁿ

Given values l₀ = 49.7mm, l =51.7mm , n =0.2 , σ(t) =379Mpa

379 x 10⁶ = K (㏑(51.7/49.7))^0.2

K = 379 x 10⁶/(㏑(51.7/49.7))^0.2

K = 723.48 MPa

Knowing the constant value would be same as the same material is being used in the second test, we can find out the true stress using the above formula replacing the value of the constant.

σ(t) = K(㏑(l/l₀))ⁿ

l₀ = 49.7mm, l = 51.7mm, n = 0.2, K = 723.48Mpa

σ(t) = 723.48 x 106 x (㏑(51.7/49.7))^0.2

σ(t) = 379 MPa

The true stress necessary to plastically elongate the specimen is 379 MPa.

6 0
3 years ago
Read 2 more answers
What do nonmetals and metals seek to do when having full outermost shells?
IceJOKER [234]

Answer: C

Explanation:

5 0
2 years ago
What causes hot air to rise, and cool air to sink?
nataly862011 [7]

Answer:

hot air rises because gases expand as they heat up.When air heats up and expands,its density also increases.The warmer,less dense air effectively floats on top of the colder, dense air below it. This creates a buoyant force that causes warmer air to rise.

cold air sinks because it is heavier as its more dense ( because of closely packed molecules) soits harder for them to move and they absorb less energy. Also, gravity pulls on it more strongly.

Hope it helps :)

8 0
3 years ago
Question 2*
Paraphin [41]

Answer:

Sc(OH)₃ = 96 g/mol

Explanation:

Gram formula mass:

Gram formula mass is the atomic mass of one mole of any substance.

It can be calculated by adding the mass of each atoms present in substance.

Sc(OH)₃:

Atomic mass of Sc = 45 amu

Atomic mas of O = 16 amu

There are three atoms of O = 16 ×3

Atomic mas of H = 1 amu

There are three atoms of H = 1 ×3

Gram formula mass of Sc(OH)₃:

Sc(OH)₃ = 45 ×1 + 16 ×3 + 1  ×3

Sc(OH)₃ = 96 g/mol

6 0
3 years ago
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