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allsm [11]
3 years ago
11

S-->SO2-->SO3-->H2SO4-->SO2-->H2SO3-->Na2SO3-->SO2--> Na2SO3-->Na2SO4-->BaSO4

Chemistry
1 answer:
siniylev [52]3 years ago
4 0
That is not a question/problem and makes no sense whatsoever
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Which intermolecular force is characteristic of compounds which are liquids at room temperature and have relatively high boiling
SIZIF [17.4K]
Thew answer is hydrogen bonds. 
6 0
3 years ago
"an acid is a substance that forms hydrogen ions when dissolved in water." this is an example of —
LenaWriter [7]

Answer is: this is an example of an Arrhenius acid.

An Arrhenius acid is a substance that dissociates in water to form hydrogen ions or protons (H⁺). 

For example hydrochloric acid: HCl(aq) → H⁺(aq) + Cl⁻(aq).

An Arrhenius base is a substance that dissociates in water to form hydroxide ions (OH⁻<span>). 
In this example lithium hydroxide is an Arrhenius base:</span>

LiOH(aq) → Li⁺(aq) + OH⁻(aq).


5 0
3 years ago
What is the name of CH3CH2OCH2CH3?
natali 33 [55]

Answer:

It is an ether so the nomenclature rule for naming the above compound will be:Alkoxy alkane , generally Alkoxy represent the smaller alkyl group and as in the above question both the alkyl group are same so it's IUPAC Name will be: Ethoxy ethane or Diethylether both are correct

Explanation:

happy to help ya!

5 0
3 years ago
Methylamine (ch3nh2) is a weakly basic compound. calculate the kb for methylamine if a 0.253 m solution is 4.07% ionized.
MariettaO [177]
Answer is: Kb for methylamine is 4.37·10⁻⁴.<span>
Chemical reaction: CH</span>₃NH₂ + H₂O → CH₃NH₃⁺ + OH⁻.
c(CH₃NH₂) = 0.253 M.
α = 4.07% ÷ 100% = 0.0407.
[CH₃NH₃⁺] = [OH⁻] = c(CH₃NH₂) · α.
[CH₃NH₃⁺] = [OH⁻] = 0.253 M · 0.0407.
[CH₃NH₃⁺] = [OH⁻] = 0.0103 M.
[CH₃NH₂] = 0.253 M - 0.0103 M.
[CH₃NH₂] = 0.2427 M.
Kb = [CH₃NH₃⁺] · [OH⁻] / [CH₃NH₂]. 
Kb = (0.0103 M)² / 0.2427 M.
Kb = 4.37·10⁻⁴.
8 0
3 years ago
If air is 80 percent nitrogen and 20 percent oxygen by volume what is density
Evgen [1.6K]
1 mol of any gas or mix of gases at STP conditions will have a volume of 22.4 L. Since the problem doesn’t said what are the conditions I will asume that are STP condition and the volume of one mole of the mix will have a volume of 22.4 L.

You may know that density is
D=m/v

In one mole of air I will have 80% of Nitrogen (N2) and 20% oxygen (O2).

So the mass of one mole of air will be

14 x2x0.80+16x2x0.20 = 22.4 g + 6.4 g = 28.8 g

D= 28.8/22.4 = 1.28 g/L

Of course if the temperature is higher the density will be smaller because the volume of one mole will be bigger and viceversa if the temperature decrease. Also if the pressure is different than one atm the volume of a mol will change.
5 0
3 years ago
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