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allsm [11]
3 years ago
11

S-->SO2-->SO3-->H2SO4-->SO2-->H2SO3-->Na2SO3-->SO2--> Na2SO3-->Na2SO4-->BaSO4

Chemistry
1 answer:
siniylev [52]3 years ago
4 0
That is not a question/problem and makes no sense whatsoever
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Copper metal has a specific heat of 0.385 J/goC. Calculate the amount of heat required to raise the temperature of 22.8 g of Cu
Liula [17]

Answer is equal to 7.51 kJ

Q=mc(delta)T

4 0
2 years ago
Can you help me with 2 and 3 please
Citrus2011 [14]
Bacteria --> corn --> mouse --> hawk

5 0
3 years ago
A rock that has a mass if 180 grams dropped in a graduated cylinder that was originally filled to 52ml; it now reads 62ml. What
Vlad [161]

Answer:

<h2>18 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

volume = final volume of water - initial volume of water

volume = 62 - 52 = 10 mL

From the question we have

density =  \frac{180}{10}  \\

We have the final answer as

<h3>18 g/mL</h3>

Hope this helps you

5 0
3 years ago
If a system has a reaction quotient of 2.13 ✕ 10−15 at 100°C, what will happen to the concentrations of COBr2, CO, and Br2 as th
qaws [65]

This is an incomplete question, here is a complete question.

Consider the following equilibrium at 100°C.

COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)

K_c=4.74\times 10^4

Concentration at equilibrium:

[COBr_2]=1.58\times 10^{-6}M

[Co]=2.78\times 10^{-3}M

[Br_2]=2.51\times 10^{-5}M

If a system has a reaction quotient of 2.13 × 10⁻¹⁵ at 100°c, what will happen to the concentrations of COBr₂, Co and Br₂ as the reaction proceeds to equilibrium?

Answer : The concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.

Explanation :

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given balanced chemical reaction is,

COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)

The expression for reaction quotient will be :

Q=\frac{[CO][Br_2]}{[COBr_2]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(2.78\times 10^{-3})\times (2.51\times 10^{-5})}{(1.58\times 10^{-6})}=4.42\times 10^{-2}

The given equilibrium constant value is, K_c=4.74\times 10^4

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

There are 3 conditions:

When Q>K_c that means product > reactant. So, the reaction is reactant favored.

When Q that means reactant > product. So, the reaction is product favored.

When Q=K_c that means product = reactant. So, the reaction is in equilibrium.

From the above we conclude that, the Q that means product < reactant. So, the reaction is product favored that means reaction must shift to the product (right) to be in equilibrium.

Hence, the concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.

3 0
3 years ago
What is one beneift of using scientific notation instead of regular notation
kotykmax [81]

Answer:

its shorter than a regular one

Explanation:

the only reason is simply because it is shorter

8 0
3 years ago
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