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4 years ago

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What is Potential flow?

1 answer:

nordsb [41]4 years ago

6 0

Answer: Potential flow states about the velocity field considering it as gradient of scalar function such as the velocity potential. It is considered same as irrotational flow.

Explanation:In the study of fluid dynamics , potential flow is stated as the term for describing about the velocity field taking it as the gradient of a scalar function. Therefore, potential flow is stated by an irrotational velocity field and there is a irrotation because of the curl of the gradient of scalar quantity is zero.Potential flow is considered same as the irrotational flow that is the particles in the fluids that do not rotate.

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DochEvi [55]

Answer:

Optimal aspect ratio = 1

Explanation:

From Chvorinov's Rule,

$T = c [\frac{volume}{surface are}]^n$

Where

T = solidification time

c = mold constant

$Volume = \frac{pi D^2 h}{4}$

$Surface areaA= pi Dh[\frac{2pi D^2}{4}$

For the riser to have the longest solidification time:

We have: D = h

$V = \frac{pi D^3}{4}$

$A = pi Dh[\frac{2pi D^2}{4}] = 1.5D^2 pi$

Therefore,

$\frac{V}{A} = \frac{\frac{pi D^3}{4}}{1.5D^2 pi}$

$\frac{V}{A} = \frac{D}{6}$

To have to longest solidification time, D = h

Therefore the best aspect ratio would be,

$\frac{D}{h} = 1$

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3 years ago

4.In a hydroelectric power plant, 100 m3/s of water flows from an elevation of 120 m to a turbine, where electric power is gener

Dmitrij [34]

Answer:

The rate of irreversible loss will be "55.22 MW".

Explanation:

The given values are:

Elevation,

h = 120 m

Flow of water,

Q = 100 m³/s

Efficiency,

= 80%

i.e,

= 0.8

Efficiency turbine,

= 50 MW

Now,

Without any loss,

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⇒ $P=\delta gQh$

On substituting the values, we get

⇒ $=1000\times 9.8\times 100\times 120$

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Power generated in actual will be:

= $\frac{50}{0.8}$

= $62.5 \ MW$

Hence,

Throughout the piping system,

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3 years ago

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Ludmilka [50]

Known :

Q = 300 L/s = 0.3 m³/s

D1 = 350 mm = 0.35 m

D2 = 700 mm = 0.7 m

g = 9.81 m/s²

Solution :

A1 = πD1² / 4 = π(0.35²) / 4 = 0.096 m²

A2 = πD2² / 4 = π(0.7²) / 4 = 0.385 m²

hL = (kL / 2g) • (U1² - U2²)

hL = (kL / 2g) • Q² (1/A1² - 1/A2²)

hL = (1 / 2(9.81)) • (0.3²) • (1/(0.096²) - 1/(0.385²))

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