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2 years ago

4. An electrician's pen knife often

Engineering

2 answers:

Flauer [41]2 years ago

5 0

Answer:

option d

is kept very sharp to cut wire of large thickness

Paraphin [41]2 years ago

5 0

D D D D D D D D D D D D D D

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Please help this is due today!!!!!

White raven [17]

Answer:

1:c 2:False

Explanation:

7 0

3 years ago

Wich muscle in your body are affected by alcohol first

mr Goodwill [35]

Answer:

Brain

Explanation:

<h3><em>Thirty seconds after your first sip, alcohol races into your brain. It slows down the chemicals and pathways that your brain cells use to send messages. That alters your mood, slows your reflexes, and throws off your balance.</em></h3>

8 0

3 years ago

When an airplane is flying 200 mph at 5000-ft altitude in a standard atmosphere, the air velocity at a certain point on the wing

Alexandra [31]

Answer:

Pressure = $P2=73.13 lbf/ft^2$

Explanation:

The pressure is calculated by Bernoulli's equation.

$P1+\frac{1}{2} dVi^2=P2+\frac{1}{2} dVf^2\\$

Solving it for P2

$P2=P1 +\frac{1}{2} d(Vi^2-Vf^2)$

Now inserting values

P1 = 0 as it is given that initial point is at atmospheric point.

d= density = 2.05 sl/ft3

Vi = 200 mph = 293.33 ft/s

Vf = 273 mph = 400.4 ft/s

Putting these values

$P2 = 0 + 0.5* 2.05(293.33^2-400.4^2)\\P2=-76sl/ft.s^2$

Changing the units to pounds per square foot

$P2=73.13 lbf/ft^2$

7 0

4 years ago

A 0.2‐kg particle P is constrained to move along the vertical‐plane circular slot of radius r = 0.5 m and is confined to the slo

Pavel [41]

Answer:

● The force N exerted on the particle by the circular constraint= -2.885 N

● The force R exerted on it by the slotted arm= 1.599 N

Explanation:

The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.

8 0

3 years ago

Suppose we are managing a consulting team of expert computer hackers, and each week we have to choose a job for them to undertak

lina2011 [118]

Answer:

if number == 1

then

tempSolution= max(l[number],h[number])

else if number == 2 then

tempSolution= max(optimalPlan(1, l, h)+ l[2], h[2])

else

tempSolution= max(optimalPlan(number − 1, l, h) + l[number], optimalPlan(number − 2, l, h) + h[number])

end if

return Value

FindOptimalValue(number, l, h)

for itterator = 1 ! number do

tempSolution[itterator] = 0

end for

for itterator = 1 ! number do

if itterator == 1 then

tempSolution[itterator] max(l[itterator], h[itterator])

else if itterator == 2 then

tempSolution[itterator] max(tempSolution[1] + l[2], h[2])

else

tempSolution[itterator] max(tempSolution[itterator − 1] + l[itterator], tempSolution[itterator − 2] + h[itterator])

end if

end for

return Value[number]

OPtimalPlan(number, l, h, Value)

for itterator = 1 ! number do

WeekVal[itterator]

end for

if tempSolution[number] − l[number] = tempSolution[number − 1] then

WeekVal[number] ”Low stress”

OPtimalPlan(number-1, l, h, Value)

else

WeekVal[number] ”High stress”

OPtimalPlan(number-2, l, h, Value)

end if

return WeekVal

7 0

3 years ago