The solution would be like
this for this specific problem:
<span>5.5 g = g + v^2/r </span><span>
<span>4.5 g =
v^2/r </span>
<span>v^2 = 4.5
g * r </span>
<span>v = sqrt
( 4.5 *9.81m/s^2 * 350 m) </span>
v = 124
m/s</span>
So the pilot will black out for this dive at 124
m/s. I am hoping that these answers have satisfied your query and it
will be able to help you in your endeavors, and if you would like, feel free to
ask another question.
But
- Hence higher the radius lower the voltage
- Lower the voltage higher the capacitance .
<h3>100cm diameter having aluminium sphere has a larger capacitance</h3>
<span>Slowing an
object down is not a means of accelerating it. It actually decelerates the
motion of an object. Speeding it up, changing its direction and applying
balanced forces accelerate an object. In order for an object to accelerate, a force
must be applied. It follows Newton’s second law of motion where it states that
a body at rest remains at rest unless a force is acted upon it. When you move
an object, you are exerting a force onto it. By exerting a force on the object,
you are actually displacing it from its initial position. You cannot apply
force to the object without altering its position. Keep in mind that when you
exert work, you are exerting energy too. </span>
ummmm it might be 300... i used a calculator
sorry if it is wrong
