The answer is 29.0576 m/s
Considering the equivalence between mass and energy given by the expression of Einstein's theory of relativity, the correct answer is the last option: the energy equivalent of an object with a mass of 1.05 kg is 9.45×10¹⁶ J.
The equivalence between mass and energy is given by the expression of Einstein's theory of relativity, where the energy of a body at rest (E) is equal to its mass (m) multiplied by the speed of light (c) squared:
E=m×c²
This indicates that an increase or decrease in energy in a system correspondingly increases or decreases its mass, and an increase or decrease in mass corresponds to an increase or decrease in energy.
In other words, a change in the amount of energy E, of an object is directly proportional to a change in its mass m.
In this case, you know:
Replacing:
E= 1.05 kg× (3×10⁸ m/s)²
Solving:
<u><em>E= 9.45×10¹⁶ J</em></u>
Finally, the correct answer is the last option: the energy equivalent of an object with a mass of 1.05 kg is 9.45×10¹⁶ J.
Learn more:
Answer:
The flow of matter and energy in the ecosystems is important so that the exchange necessary for them to work. In order for ecosystems to exist, there must be energy flowing and making possible the transformation of matter. Ecosystems are complex systems that exchange matter and energy with the environment and, as a result, modify it.
Explanation:
Answer:
The reading of the experiment made in air is 50 g more than the reading of the measurement made in water.
Explanation:
Knowing that the density of lead is 
and the volume, we can calculate the true weight of the piece of lead:
When the experiment is done in air, we can discard buoyancy force (due to different densities) made by air because it's negligible and the measured weight is approximately the same as the true weight.
When it is done in water, the effect of buoyancy force (force made by the displaced water) is no longer negligible, so we have to take it into account.
Knowing that the density of water is 1 g per cubic centimeter, and that the volume displaced is equal to the piece of lead (because of its much higher density, the piece of lead sinks), we can know that the buoyancy force made by water is 50 g, opposite to the weight of the lead.
Now that we have the two measurements, we can calculate the difference:
The reading of the experiment made in air is 50 g more than the reading of the measurement made in water.
