The acceleration due to gravity near the surface of the planet is 27.38 m/s².
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Acceleration due to gravity near the surface of the planet</h3>
g = GM/R²
where;
- G is universal gravitation constant
- M is mass of the planet
- R is radius of the planet
- g is acceleration due to gravity = ?
g = (6.626 x 10⁻¹¹ x 2.81 x 5.97 x 10²⁴) / (6371 x 10³)²
g = 27.38 m/s²
Thus, the acceleration due to gravity near the surface of the planet is 27.38 m/s².
Learn more about acceleration due to gravity here: brainly.com/question/88039
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Meter <span>per second (U.S. spelling: </span>meter<span> per second) is an SI derived unit of both speed (scalar) and velocity (vector quantity which specifies both magnitude and a specific direction), defined by distance in meters divided by time in seconds. The SI unit symbols are m.</span>
Potential Energy= 24m * 14kg * 9.8N/kg = 3292.8J
Answer:
its center of gravity lies over its base of support.
Explanation:
An object will be stable if its center of gravity lies over its base of support.
When an object is balanced so that a displacement lowers its center of gravity, the object is said to be in stable equilibrium.