The work done is 400 J
Explanation:
The work done by you in pushing the box along the slope is given by
where
F is the magnitude of the force applied
d is the distance covered by the box along the slope
Here we have the following:
F = 200 N is the magnitude of the force applied
is the distance covered, where
h = 1 m is the vertical rise
is the slope of the plane
Substituting and solving, we find
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The electric output of the plant is 48.19 MW
First we need to calculate the water power, it is given by the formula
WP=ρQgh
Here, ρ=1000 kg/m3 is density of water,Q is the flow rate, g is the gravity, and h is the water head
Therefore, WP=1000*65*9.81*90=57388500 W=57.38 MW
Now the overall efficiency of the hydroelectric power plant is given as
η=
Plugging the values in the above equation
0.84=EP/57.38
EP=48.19 MW
Therefore, the electric output of the plant is 48.19 MW.
Explanation:
Below is an attachment containing the solution.
Answer:
The value is
Explanation:
From the question we are told that
The initial speed is
Generally the total energy possessed by the space probe when on earth is mathematically represented as
Here is the kinetic energy of the space probe due to its initial speed which is mathematically represented as
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And is the kinetic energy that the space probe requires to escape the Earth's gravitational pull , this is mathematically represented as
Here is the escape velocity from earth which has a value
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Generally given that at a position that is very far from the earth that the is Zero, the kinetic energy at that position is mathematically represented as
Generally from the law energy conservation we have that
So
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