Compression- a region in a longitudinal (sound) wave where the particles are closest together. Rarefaction- a region in a longitudinal (sound) wave where the particles are furthest apart. Wave motion and particles.
Answer is B.
Let's list the given information. The frictional force, denoted as Ff, is equal to 0.200 N. We have to find the normal force, denoted as Fn. The relationship between Ff and Fn is written as:
Ff = μFn
where μ is the coefficient of friction
If there is no given data for μ, we can't solve this problem. Suppose μ = 0.5, then the normal force would be:
Fn = Ff/μ = 0.2/0.5 = 0.4 N
The appropriate response is false. Cathode-beam ray does not deliver pictures on the guideline of instigated emf. The cathode-ray is a high-vacuum tube in which cathode beams deliver an iridescent picture on a fluorescent screen, utilized mostly in TVs and workstations.
Answer:
Explanation:
A lot. That's why he was one of Boston's star hitters.
m = 0.15 kg
a = 3.0 * 10^4
F = ?
F = 0.15 * 3*10^4
F = 0.45 * 10^4
F = 4.5 * 10^3 Newtons
You should always express scientific notation as a number between 1 and 10 or 1 < x < 10. The power will determine the exact value of the number expressed as a scientific notation.
Answer:
The initial volume of the system is 2.7 L
Explanation:
The change in internal energy is given by;
ΔU = Q - W
where;
Q is the heat absorb from the surrounding
W is the work done by the system
Given;
ΔU = -107.6 J
Q = 59 J
W = ?
W = Q- ΔU
W = 59J - (-107.6)
W = 166.6 J
Work done is given by;
W = PΔV
W = P(V₂ - V₁)
101.325 Joules = 1 L.atm
166.6 Joules = ?
= 1.644 L.atm
1.644 L.atm = 0.543 atm(57.7L - V₁)
57.7L - V₁ = (1.644 L.atm) / (0.543 atm)
57.7L - V₁ = 3.0 L
V₁ = 57.7L - 3.0 L
V₁ = 2.7 L
Therefore, the initial volume of the system is 2.7 L
