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Nutka1998 [239]
3 years ago
7

A.complete the following sentences with your own result or condition

Physics
1 answer:
ludmilkaskok [199]3 years ago
6 0

1. If I hadn't bought that car yesterday.

2. I would have never bought the tickets for today..

3. She wouldn't have gotten suspended.

4. We could've worked on our project.

5. but I was in the shower.

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This is a compound made from a group of covalently bonded atoms.
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The answer is molecule
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If F(theta)=tan theta=3, find F(theta+pi)
Alex_Xolod [135]
The period of the tan function is π so (∅ + π) would yield the same value as ∅
F(∅ + π) = 3
4 0
2 years ago
How much work does the electric field do in moving a proton from a point with a potential of +145 v to a point where it is -55 v
Aleks04 [339]
The work done by the electric field in moving a charge is the negative of the potential energy difference between the two locations, which is the product between the magnitude of the charge q and the potential difference \Delta V:
W=-\Delta U=-q\Delta V=-q (V_f -V_i)
The proton charge is q=1.6 \cdot 10^{-19}C, and the two locations have potential of V_i = +145 V and V_f=-55 V, therefore the work is
W=-(1.6 \cdot 10^{-19}C)(-55 V-(+145 V))=3.2 \cdot 10^{-17}J
5 0
2 years ago
What is the focal length (in meters) of a lens whose radius of curvature is 9. 2 m and has a refractive index 1. 2?
Fed [463]

The focal length (in meters) of a lens whose radius of curvature is 9. 2 m and has a refractive index  1.2 will be 18.4 m

The focal length of a lens is determined when the lens is focused at infinity. Lens focal length tells us the angle of view—how much of the scene will be captured—and the magnification—how large individual elements will be.

Focal length of a lens is the distance between center of lens and focal point . Focal point is a point on principal axis , at which light rays parallel to principal axis meet after refraction through lens or seem to meet after refraction .

The radius of curvature is the radius of sphere formed by the convex or concave mirror. It is also equal to the distance between the pole and center of curvature. The sign convention for focal length and radius of curvature is the same.

focal length = 2 * radius of curvature

given

radius of curvature = 9.2 m

focal length = 2 * 9.2

                    = 18.4 m

To learn more about focal length here

brainly.com/question/16188698

#SPJ4

4 0
2 years ago
When the ball of the pendulum moves from (x) to (y) in a duration of 0.02 sec the frequency equals
Mariulka [41]
0.4 sec the frequency equals
5 0
1 year ago
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