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natima [27]
3 years ago
13

Un móvil se desplaza con una rapidez inicial de 100 km/h, se le aplican los frenos con una

Physics
1 answer:
KIM [24]3 years ago
4 0

Answer:

in English please I am quite puzzled

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How is work calculated when the force applied is not parallel to the displacement
Leno4ka [110]
Pretty sure it’s Force*Distance*Cos(theta)
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Note that the scale bar under the photo is labeled 1 μm (micrometer). The scale bar works the same way as a scale on a map, wher
AnnZ [28]

Answer:

Hello your question has some missing parts attached below is the complete question

answer : 4 μm

Explanation:

since the scale bar works the same way as a scale on a map , each bar will therefore represent 1 μm and the mature parent cell's is about 4 times the labeled value hence the Mature parent cell diameter will approximately be : 4 μm

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3 years ago
What change will always result in an increase in gravitational force between two objects
tekilochka [14]

The gravitational force between two object depends on their masses and on their distance.


Since the formula is


F = G\frac{m_1m_2}{d^2}


If the masses grow, the force also grows. But I'm assuming the two objects are fixed, so you can't enlarge their mass.


So, the only option remaining is to lower their distance: since it sits at the denominator, a smaller value of d results in a bigger value for F.


So, if you reduce the distance between two objects, the gravitational force between them will always result in an increase

6 0
3 years ago
A 7.00 kg bowling ball is held 2.00 m above the ground. Using g = 9.80 m/s2, how much energy does the bowling ball have due to i
deff fn [24]
mgh =7*2*9.8=137.2. It should be the answer.
4 0
3 years ago
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A garden hose has a radius of 0.0120 m, and water initially comes out at a speed of 2.88m/s. Dasha puts her thumb over the end ,
creativ13 [48]

Answer:

v = 12.4 [m/s]

Explanation:

With the speed and Area information, we can determine the volumetric flow.

V=v*A\\A=\pi *r^{2}

where:

r = radius = 0.0120 [m]

v = 2.88 [m/s]

A=\pi *(0.0120)^{2} \\A=4.523*10^{-4} [m]\\

Therefore the flow is:

V=2.88*4.523*10^{-4} \\V=1.302*10^{-3} [m^{3}/s ]

Despite the fact that you cover the inlet with the finger, the volumetric flow rate is the same.

v=V/A\\v=1.302*10^{-3} /1.05*10^{-4} \\v=12.4[m/s]

3 0
3 years ago
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