Answer:
a = -4/5 m/s^2
Explanation:
Acceleration = change in velocity / time
change in velocity = final velocity - initial velocity
a = (20 m/s - 60 m/s) / 50 s
a = -40 m/s / 50 s
a = -4/5 m/s^2
hope this helps! <3
Answer:
Option (b) is correct.
Explanation:
Elastic collision is defined as a collision where the kinetic energy of the system remains same. Both linear momentum and kinetic energy are conserved in case of an elastic collision.
Inelastic collision is defined as a collision where kinetic energy of the system is not conserved whereas the linear momentum is conserved. This loss of kinetic energy may due to the conversion to thermal energy or sound energy or may be due to the deformation of the materials colliding with each other.
As given in the problem, before the collision, total momentum of the system is
and the kinetic energy is
. After the collision, the total momentum of the system is
, but the kinetic energy is reduced to
. So some amount of kinetic energy is lost during the collision.
Therefor the situation describes an inelastic collision (and it could NOT be elastic).
Explanation:
Given that,
Size of object, h = 0.066 m
Object distance from the lens, u = 0.210 m (negative)
Focal length of the converging lens, f = 0.14 m
If v is the image distance from the lens, we can find it using lens formula as follows :
(a) Magnification,
![m=\dfrac{v}{u}\\\\m=\dfrac{0.42}{(-0.21)}\\\\m=-2](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7Bv%7D%7Bu%7D%5C%5C%5C%5Cm%3D%5Cdfrac%7B0.42%7D%7B%28-0.21%29%7D%5C%5C%5C%5Cm%3D-2)
(b) Magnification, ![m=\dfrac{h'}{h}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7Bh%27%7D%7Bh%7D)
h' is image height
![-2=\dfrac{h'}{0.066}\\\\h'=-2\times 0.066\\\\h'=-0.132\ m](https://tex.z-dn.net/?f=-2%3D%5Cdfrac%7Bh%27%7D%7B0.066%7D%5C%5C%5C%5Ch%27%3D-2%5Ctimes%200.066%5C%5C%5C%5Ch%27%3D-0.132%5C%20m)
Hence, this is the required solution.
Answer:
35m/s[57o].
X = 35*Cos57 =
Y = 35*sin7 =Explanation:
learn man but there u go
![\\ \bull\sf\dashrightarrow F=ma](https://tex.z-dn.net/?f=%5C%5C%20%5Cbull%5Csf%5Cdashrightarrow%20F%3Dma)
![\\ \bull\sf\dashrightarrow a=\dfrac{F}{m}](https://tex.z-dn.net/?f=%5C%5C%20%5Cbull%5Csf%5Cdashrightarrow%20a%3D%5Cdfrac%7BF%7D%7Bm%7D)
Now
![\\ \bull\sf\dashrightarrow a\propto\dfrac{1}{m}](https://tex.z-dn.net/?f=%5C%5C%20%5Cbull%5Csf%5Cdashrightarrow%20a%5Cpropto%5Cdfrac%7B1%7D%7Bm%7D)
![\\ \bull\sf\dashrightarrow a\propto F](https://tex.z-dn.net/?f=%5C%5C%20%5Cbull%5Csf%5Cdashrightarrow%20a%5Cpropto%20F)
- Lower mass=Higher acceleration
- Lower Force=Lower Acceleration
Option B has lowest mass and highest force hence its correct