A) Work energy relation;
Work =ΔKE ; work done = Force × distance, while, Kinetic energy = 1/2 MV²
F.s = 1/2mv²
F× 4×10^-2 = 1/2 × 5 ×10^-3 × (600)²
F = 900/0.04
= 22500 N
Therefore, force is 22500 N
b) From newton's second law of motion;
F = Ma
Thus; a = F/m
= 22500/(5×10^-3)
= 4,500,000 m/s²
But v = u-at
0 = 600- 4500,000 t
t = 1.33 × 10^-4 seconds
Velocity is speed with direction. So, if velocity varies directly with speed, that statement would be true. A constant velocity would resort in a constant speed. They are connected and are dependant on each other.
I hope this helps!
~kaikers
Answer: Some conversions from one system of units to another need to be exact, without increasing or decreasing the precision of the first measurement. This is sometimes called soft conversion. It does not involve changing the physical configuration of the item being measured.
Explanation:
Ohm's law states that V = IR
87 = 2 x R
R = 87/2 ohms
Hope this helps :)
Answer:
5.42 s
Explanation:
Using the equation of motion,
v = u + at ..................... Equation 1,
Where v = Final velocity, u = initial velocity, a = acceleration, t = time.
Making t the subject of the equation,
t = (v-u)/a ....................... Equation 2
Note: When the the bicycle is brought to a complete stop, the final velocity of the bicycle is 0 m/s and the bicycle is decelerating.
Given: v = 0 m/s, u = 6.5 m/s, a = - 1.2 m/s² ( decelerating).
Substituting into equation 2
t = (0-6.5)/-1.2
t = -6.5/-1.2
t = 5.42 s.
Hence the time take for the cyclist to bring the bicycle to complete stop = 5.42 s