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Black_prince [1.1K]
3 years ago
12

The graph below shows the distance traveled by the skateboarder on each of the different road conditions. Using the graph, deter

mine which of the roads was dry, wet, or muddy. Explain your answer using complete sentences.
Physics
1 answer:
igor_vitrenko [27]3 years ago
6 0

Answer:

Road A- dry

Road B- mud

Road C- wet

Explanation:

Surface conditions do affect the ease and speed with which a skateboarder can move, on a muddy surface, the tyres of the skate boards finds it difficult to establish adequate fictional force between the skates trees and the traveling surface. Hence, the muddy surface presents a very slippery travel ground for the skate, hence leading the to skateboarder needing to apply caution.

The speed on a wet surfave is height as the amount of firece that will be applied in other to accelerate is very small. The surface is wet and hence serves as a lubricant between the contact surface.

The dry road also has a high speed but lower than a wet surface, frictional force is high here and this tend to slow the skateboarder down except in sloppy terrains.

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<span>∴ rate is also measurable and ∴ quantitative.

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3 years ago
a ball drops some distance and loses 30 j of gravitational potential energy. do not ignore air resistance. how much kinetic ener
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Thus, more than 30 J of potential energy can be loosed by the ball. Thus, the gravitational potential energy of the ball is more than 30 J.

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5 0
1 year ago
Which of the following is not an example of an engine?
SashulF [63]
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4 0
3 years ago
Assuming the input of energy continues for another 2.5 seconds, where will the particle be?
VladimirAG [237]
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3 0
3 years ago
A hockey puck sliding on smooth ice at 4 m/s comes to a 1-m-high hill. Will it make it to the top of the hill?
solniwko [45]

Answer:

No  it will not make to the top of the hill  

Explanation:

From the question we are told that

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Generally from the law of energy conservation we have that

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So

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=>    \frac{1}{2}   * v^2 =    g *  h_{max}

=>     h_{max} =   \frac{0.5 * v^2}{g}

=>     h_{max} =  0.8163 \  m

Given that the maximum height which the pluck can get to at this speed given in the question is less than the height of the hill then conclusion will be that the pluck will not make it to the top of the hill

     

3 0
3 years ago
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