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N76 [4]
3 years ago
9

Iodine would have chemical properties most like -

Chemistry
1 answer:
MaRussiya [10]3 years ago
3 0
Iodine would have chemical properties most like H. chlorine.
They would have similar chemical properties because they belong to the same group in the periodic system of elements, unlike manganese, tellurium, and xenon. To see which group these belong to, just look at the periodic system vertically. 

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How many miles of a gas at 100 c does it take to fill a 1.00 l flask to a pressure of 152kPa
Hatshy [7]

The complete question is as follows: How many moles of a gas at 100 c does it take to fill a 1.00 l flask to a pressure of 152kPa

Answer: There are 0.0489 moles of a gas at 100^{o}C is required to fill a 1.00 l flask to a pressure of 152kPa.

Explanation:

Given: Volume = 1.00 L,    

Pressure = 152 kPa (1 kPa = 1000 Pa) = 152000 Pa

Convert Pa into atm as follows.

1 Pa = 9.86 \times 10^{-6} atm\\152000 Pa = 152000 \times \frac{9.86 \times 10^{-6}atm}{1 Pa}\\= 1.5 atm

Temperature = 100^{o}C = (100 + 273) K = 373 K

Using the ideal gas formula as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\1.5 atm \times 1.0 L = n \times 0.0821 L atm/mol K \times 373 K\\n = \frac{1.5 atm \times 1.0 L}{0.0821 L atm/mol K \times 373 K}\\n = 0.0489 mol

Thus, we can conclude that there are 0.0489 moles of a gas at 100^{o}C is required to fill a 1.00 l flask to a pressure of 152kPa.

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3 years ago
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Pregunta en guglu ay te ayudara
8 0
3 years ago
Find the mass of 3.27 x 10^23 molecules of H2SO4. Use 3 significant digits<br> and put the units.
marta [7]

Answer:

Approximately 53.3\; \rm g.

Explanation:

Lookup Avogadro's Number: N_{\rm A} = 6.02\times 10^{23}\; \rm mol^{-1} (three significant figures.)

Lookup the relative atomic mass of \rm H, \rm S, and \rm O on a modern periodic table:

  • \rm H: 1.008.
  • \rm S: 32.06.
  • \rm O: 15.999.

(For example, the relative atomic mass of \rm H is 1.008 means that the mass of one mole of \rm H\! atoms would be approximately 1.008\! grams on average.)

The question counted the number of \rm H_2SO_4 molecules without using any unit. Avogadro's Number N_{\rm A} helps convert the unit of that count to moles.

Each mole of \rm H_2SO_4 molecules includes exactly (1\; {\rm mol} \times N_\text{A}) \approx 6.02\times 10^{23} of these \rm H_2SO_4 \! molecules.

3.27 \times 10^{23} \rm H_2SO_4 molecules would correspond to \displaystyle n = \frac{N}{N_{\rm A}} \approx \frac{3.27 \times 10^{23}}{6.02 \times 10^{23}\; \rm mol^{-1}} \approx 0.541389\; \rm mol of such molecules.

(Keep more significant figures than required during intermediary steps.)

The formula mass of \rm H_2SO_4 gives the mass of each mole of \rm H_2SO_4\! molecules. The value of the formula mass could be calculated using the relative atomic mass of each element:

\begin{aligned}& M({\rm H_2SO_4}) \\ &= (2 \times 1.008 + 32.06 + 4 \times 15.999)\; \rm g \cdot mol^{-1} \\ &= 98.702\; \rm g \cdot mol^{-1}\end{aligned}.

Calculate the mass of approximately 0.541389\; \rm mol of \rm H_2SO_4:

\begin{aligned}m &= n \cdot M \\ &\approx 0.541389\; \rm mol \times 98.702\; \rm g \cdot mol^{-1}\\ &\approx 53.3\; \rm g\end{aligned}.

(Rounded to three significant figures.)

6 0
3 years ago
Adding more baking soda and vinegar to the bag in the Air Bag Lab resulted in faster production of gaseous products True False
nika2105 [10]

Answer:

True

Explanation:

The more of each substanse that you add to the bag will cause it to produce faster and more gas.

5 0
3 years ago
Are roots or plant growth making cracks in concrete chemical or mechanical weathering?
OverLord2011 [107]

Answer:

it is technically biological weathering but mechanical works as well

7 0
3 years ago
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