All categories

2 years ago

What is the study of organism at the early stages of devolopment

Chemistry

1 answer:

egoroff_w [7]2 years ago

6 0

Answer: Embryology

Explanation:

You might be interested in

On September 23 The earths axis is tilted which way?

Mariana [72]

Answer:

The earth is tilted so its perpendicular

Explanation:

Because its straight up and down

3 0

2 years ago

Convert 22 grams of copper Il chloride (Cucl2) to moles. <br>with work please

Fittoniya [83]

Hope this helps!

https://youtu.be/MT5tKijKZwQ

5 0

2 years ago

Read 2 more answers

Will Mark Brainliest!!

Vikentia [17]

Answer -

1.4 g water

Hope this helps! ^^

8 0

3 years ago

What is the ph of with a 4.6 x 10-6 M hydroxide ion concentration?

nlexa [21]

<h3>Answer:</h3>

pH = 8.66

<h3>Explanation:</h3>

The pH refers to the acidity or alkalinity of a solution.
It is calculated by getting the negative logarithm of Hydrogen ions concentration.

pH=-log[H⁺]

In this case;

we are given [OH⁻] as 4.6 x 10^-6 M

We are required to calculate the pH

We need to know that;

pH + pOH = 14

pOH = -log[OH⁻]

To get the pH we can calculate the pOH first,

pOH = -log[4.6 x 10^-6 M]

= 5.34

but, pH + pOH = 14

Therefore, pH = 14 - pOH

= 14 - 5.34

= 8.66

Therefore, the pH of the solution is 8.66

3 0

2 years ago

Aqueous sulfuric acid (H2SO4) reacts with solid sodium hydroxide (NaOH) to produce aqeous sodium sulfate (Na2SO4) and liquid wat

Pie

Answer:

Theoretical yield = 8.55 g

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

For $H_2SO_4$

Mass of water = 5.9 g

Molar mass of water = 98.079 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{5.9\ g}{98.079\ g/mol}$

$Moles\ of\ Sulfuric\ acid= 0.0602\ mol$

Given: For $NaOH$

Given mass = 6.6 g

Molar mass of NaOH = 39.997 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{6.6\ g}{39.997\ g/mol}$

$Moles\ of\ NaOH= 0.1650\ mol$

According to the given reaction:

$2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O$

1 mole of sulfuric acid reacts with 2 moles of NaOH

So,

0.0602 mole of sulfuric acid reacts with 2*0.0602 moles of NaOH

Moles of NaOH = 0.1204 moles

Available moles of $NaOH$ = 0.1650 moles

Limiting reagent is the one which is present in small amount. Thus, $H_2SO_4$ is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of sulfuric acid produces 1 mole of sodium sulfate

So,

0.0602 mole of sulfuric acid produces 0.0602 mole of sodium sulfate

Moles of sodium sulfate = 0.0602 mole

Molar mass of sodium sulfate = 142.04 g/mol

Mass of sodium sulfate = Moles × Molar mass = 0.0602 × 142.04 g = 8.55 g

<u>Theoretical yield = 8.55 g </u>

3 0

3 years ago