1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
rosijanka [135]
3 years ago
7

A cation is a metallic ion derived from base.Why is it derived from base?Can you derive it from an acid?

Chemistry
1 answer:
Scorpion4ik [409]3 years ago
7 0

Answer:the cation can't be drived from an acid

Explanation:

Example

HCL+MgOH2=MgCl2+H2O

The cation in the salt magnesium chloride is magnesium which is derived from the base and the anion chlorine from the acid hydrochloric acid. The same is true in water.

Please can you add as brainleist please!!!!!!!!!!!!!!!!!!!!

You might be interested in
The variables for this experiment include the physical properties of the solutions and the pH of each solution. Use the drop-dow
Sever21 [200]

Answer:

B,D

Explanation:

In December, a city in the Southern Hemisphere has warm weather all month long.

What causes this to happen?

The city experiences fewer hours of daylight.

The city is experiencing a winter solstice.

There is a high concentration of the Sun’s rays in that region.

The Sun reaches its highest point in the sky during this month.In December, a city in the Southern Hemisphere has warm weather all month long.

What causes this to happen?

The city experiences fewer hours of daylight.

The city is experiencing a winter solstice.

There is a high concentration of the Sun’s rays in that region.

The Sun reaches its highest point in the sky during this month.

6 0
3 years ago
Read 2 more answers
Which linkages in starch and triglycerides result from condensation reactions? glycosidic bonds in starch and ester bonds in tri
bogdanovich [222]
Glycosidic bonds in starch and ester bonds in triglycerides. The glycosidic bond is considered to be the covalent synthetic bonds that connection ring-molded sugar particles to different atoms. The frame by a buildup response between a liquor or amine of one particle and the anomeric carbon of the sugar, and hence, might be O-connected or N-connected.
7 0
3 years ago
If the half-life of a radioisotope is 10,000 years, the amount remaining after 20,000 years is
Cloud [144]

Answer:

Considering the half-life of 10,000 years, after 20,000 years we will have a fourth of the remaining amount.

Explanation:

The half-time is the time a radioisotope takes to decay and lose half of its mass. Therefore, we can make the following scheme to know the amount remaining after a period of time:

Time_________________ Amount

t=0_____________________x

t=10,000 years____________x/2

t=20,000 years___________x/4

During the first 10,000 years the radioisotope lost half of its mass. After 10,000 years more (which means 2 half-lives), the remaining amount also lost half of its mass. Therefore, after 20,000 years, the we will have a fourth of the initial amount.

6 0
4 years ago
What is the balanced form of the chemical equation shown below?<br> N2(g) + H2(g) → NH3(g)<br> -
Rom4ik [11]
To balance equations you have to have same number of atoms on both sides of the equation just multiply with a suitable digit

6 0
2 years ago
A mixture of 15.0 g of the anesthetic halothane (C2HBrClF3 197.4 g/mol) and 22.6 g of oxygen gas has a total pressure of 862 tor
AlexFokin [52]

Answer : The partial pressure of C_2HBrClF_3 and O_2 are, 84 torr and 778 torr respectively.

Explanation : Given,

Mass of C_2HBrClF_3 = 15.0 g

Mass of O_2 = 22.6 g

Molar mass of C_2HBrClF_3 = 197.4 g/mole

Molar mass of O_2 = 32 g/mole

First we have to calculate the moles of C_2HBrClF_3 and O_2.

\text{Moles of }C_2HBrClF_3=\frac{\text{Mass of }C_2HBrClF_3}{\text{Molar mass of }C_2HBrClF_3}=\frac{15.0g}{197.4g/mole}=0.0759mole

and,

\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{22.6g}{32g/mole}=0.706mole

Now we have to calculate the mole fraction of C_2HBrClF_3 and O_2.

\text{Mole fraction of }C_2HBrClF_3=\frac{\text{Moles of }C_2HBrClF_3}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.0759}{0.0759+0.706}=0.0971

and,

\text{Mole fraction of }O_2=\frac{\text{Moles of }O_2}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.706}{0.0759+0.706}=0.903

Now we have to partial pressure of C_2HBrClF_3 and O_2.

According to the Raoult's law,

p^o=X\times p_T

where,

p^o = partial pressure of gas

p_T = total pressure of gas

X = mole fraction of gas

p_{C_2HBrClF_3}=X_{C_2HBrClF_3}\times p_T

p_{C_2HBrClF_3}=0.0971\times 862torr=84torr

and,

p_{O_2}=X_{O_2}\times p_T

p_{O_2}=0.903\times 862torr=778torr

Therefore, the partial pressure of C_2HBrClF_3 and O_2 are, 84 torr and 778 torr respectively.

6 0
3 years ago
Other questions:
  • A solution is made by dissolving 23.5 grams of glucose (C6H12O6) in 0.245 kilograms of water. If the molal freezing point consta
    10·1 answer
  • What is one use of the mineral gypsum fertilizer medicine wallboard electrical insulator
    14·2 answers
  • How many electrons does nitrogen (N) need to gain to have a stable outer electron shell
    9·2 answers
  • What condition must be met for a battery to be rechargeable?
    15·1 answer
  • Calculate the mass volume percent of a NaCl solution in which 186 g of NaCl is dissolved in enough water to give a total volume
    14·1 answer
  • 1) For the following molecules: - Draw the Lewis structures/dots - Determine the polarity (polar or non-polar). - List all inter
    11·1 answer
  • Generally, does the size of a radioactive sample affect half-life?
    8·2 answers
  • Hypothetical element X has 3 stable isotopes. The relative peak intensities are 79.52 for 180.0 u, 100.0 for 184.0 u, and 82.98
    14·1 answer
  • BRAINLIEST IF ANSWERED CORRECTLY WITH EXPLANATION! HELP PLEASE:)
    15·1 answer
  • How is a line spectra created from a hot gas? a. photons are emitted when the amount of radioactive material in the gas decrease
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!